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Misha Larkins [42]
4 years ago
15

Assuming the compound is dissolved in water,what is the formula for phosphorus acid?

Chemistry
1 answer:
marishachu [46]4 years ago
5 0
The answer is H3PO3.

The formula for phosphorus acid would be H3PO3 assuming that this compound is dissolved in water. <span>This acid is diprotic, not triprotic as might be suggested by this formula. Phosphorous acid is an intermediate in the preparation of other phosphorus compounds.</span>

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Gloria is writing the chemical formula for a compound using its chemical name. She has just identified the names of the elements
disa [49]
She will use the periodic table of elements to not only find out the chemical symbols of the elements written within the name, but also to check whether or not the elements are metals and or nonmetals, from this determine the ionic charges if needed for metals, and for metals that have more than one ionic charge, use a Roman numeral to represent the ionic charge that she would be using in writing the chemical formula of the compound.
5 0
4 years ago
Read 2 more answers
The rate of a hypothetical reaction involving L and M is found to double when the concentration of L is doubled and to increase
Semmy [17]

Answer: Rate=k[L]^1[M]^2

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

L+M\rightarrow products

Rate=k[L]^x[M]^y  (1)

k= rate constant

x = order with respect to L

y = order with respect to M

n =( x+y)= Total order

a)  If [L] is doubled, the reaction rate will increase by a factor of 2:

2\times Rate=k[2L]^x[M]^y   (2)

b)  If [M] is doubled, the reaction rate will increase by a factor of 4:

4\times Rate=k[L]^x[2M]^y   (3)

Dividing 2 by 1:

\frac{2\times Rate}{Rate}=\frac{k[2L]^x[M]^y}{k[L]^x[M]^y}

2=2^x

x=1

Dividing 3 by 1

\frac{4\times Rate}{Rate}=\frac{k[L]^x[2M]^y}{k[L]^x[M]^y}

4=2^y

2^2=2^y

y=2

Thus rate law is: k[L]^1[M]^2

4 0
4 years ago
Consider the reaction in the lead-acid cell pb(s) pbo2(s) 2 h2so4(aq) 2 pbso4(aq) 2 h2o(l) for which e°cell = 2. 04 v at 298 k.
aleksley [76]

δg° for the reaction having e° cell = 2.04v. is 393.658kJ.

The lead (Pb) in the lead storage battery act as an anode

<h3>What is Voltaic Cell?</h3>

A voltaic cell or galvanic cell is an electrochemical cell that uses chemical reactions to produce electrical energy.

<h3>Parts of voltaic cell</h3>

Anode where oxidation occurs Cathode where reduction occurs.

Therefore, Pb acts as anode and PbO2 act as a cathode.

Given,

E° cell = 2.04v

Faraday constant= 96485 C/mol

Moles of electron transferred n= 2

∆G = -nFE°

= -2 × 96485 × 2.04

= 393.658kJ

Thus we concluded that the δg° for the reaction having e° cell = 2.04v. is 393.658kJ.

learn more about voltaic cell :

brainly.com/question/1370699

#SPJ4

8 0
2 years ago
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