It is defined as the amount of a substance that contains as many particles as there are atoms in 12 grams of pure carbon-12. So, 1 molecule contains 6.022×10^23 elementary entities of the substance.
Hope that helps
Answer:
0.84kg of gatorade powder
Explanation:
From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.
To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:
0.6kg of gatorade powder required 5 gallons of water.
Therefore, xkg of gatorade powder will require 7 gallons of water i.e
xkg of gatorade powder = (0.6 x 7)/5
xkg of gatorade powder = 0.84kg
Therefore, 0.84kg of gatorade powder will be required.
<h2>
Answer:</h2>
<h2>The correct option is:</h2>
<h3>D. Actions of Electrons</h3>
<h2>
Explanation:</h2>
<h3 /><h3>Bonds are formed when valence electrons, the electrons in the outermost electronic “shell” of an atom, interact. </h3>
<h2>Hope it help you </h2>
Given:
N2, volume of 1L of NH3 at STP
Required:
Grams of N2
Solution:
N2 + 3H2 -> 2NH3
Molar mass of N2 = 28g
From the ideal gas equation PV = nRT
n = PV/RT
n = (1 atm)(100 L)/(0.08206 L-atm/mol-K)(273K)
n = 4.46 mol of NH3
from the reaction, we need 2 moles of NH3 to get 1 mole of N2
4.46 mol NH3(1 mol N2/2 mol NH3) = 2.23 moles N2
2.23 moles of N2(28 g N2/1 mol N2) = 62.5g N2
