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rusak2 [61]
3 years ago
14

Eriq, a chemist, is running tests with four unknown elements. He has found that they all bond the same way, so he knows that the

y are in the same group on the periodic table of elements. The table shows other properties that Eriq observed.
A 4-column table with 4 rows titled properties of four unknown elements. The first column titled element number has entries 1, 2, 3, 4. The second column titled melting point has entries 266 K, 172 K, 387 K, 53 K. The third column titled boiling point has entries 332 K, 239 K, 457 K, 85 K. The fourth column titled phase at room temperature has entries liquid, gas, solid, gas.

These four elements are most likely in group

15.
16.
17.
18.
Chemistry
2 answers:
lana66690 [7]3 years ago
5 0
It would be element 17 would most likely go in that group
Zigmanuir [339]3 years ago
4 0

Answer:

the elements would go in group 17.

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Water is unique because
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Answer:

b. It exists in three different states at normal conditions in the Earth's atmosphere  

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D. It formed solely from atoms generated by the Big Bang.

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Which pair of elements are the most similar? A. Ca and F B. Na and Cl C. Ne and Ar D. K and Ca
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8 0
2 years ago
When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

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4 0
3 years ago
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