With the principle quantum number being 2, the maximum number that can share this is 8. You can use the general formula 2n^2 to calculate this number (n=quantum level), or you can use the concept of quantum numbers (n, l, m, s) to justify this answer.
Answer:
si es un país democrático.
justificación: el estado colombiano es una democracia sólida y fuerte, con gran tradición dentro de la región, esta tiene como eje principal la generación de empleo, buscando que todos los colombianos tengan ingresos seguros un trabajo digno y pertenezca a la seguridad social.
Explanation:
esperó te sirva
Its relative density causes objects to float or sink.
If the density of the substance is greater than the substance it is in, it will sink.
If the density is less than the substance it is in it will float.
(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ
<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>
<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>
<span>(179 kJ) / (181 kJ / 1 mol O2) x (31.99886 g O2/mol) = 31.6 g O2 </span>
<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>
<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>
<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
<span>(798 kJ) / (90.0 kJ / 2 mol HN3) x (17.03056 g NH3/mol) = 302 g NH3 </span>
<span>(19.7 g H2O) / (18.01532 g H2O/mol) x (90.0 kJ / 3 mol H2O) = 32.8 kJ</span>
First take all percents and make them grams. Since you're not given a overall molar mass you can assume it is 100 and therefore the percents are their masses.
So you have 14.31g Carbon, 1.2g Hydrogen, and 84.49g of Chlorine. Next you divide each by their molar masses to get moles of each.
Carbon= <u>14.31</u>g Hydrogen= <u>1.2</u>g Chlorine= <u>85.49</u>g
12.01g 1.01g 35.45g
= 1.19moles = 1.188moles = 2.411moles
Next you divide each of those numbers by the smallest, in this case, Hydrogen.
Thus,
Carbon= <u>1.19moles</u> Hydrogen= <u>1.188moles</u> Chlorine= <u>2.411moles</u>
1.188moles 1.188moles 1.188moles
=1.002 =1 =2.02
These are all close enough to round, so your final empirical formula is: CHCl2
Hope that helps!!