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deff fn [24]
2 years ago
9

Stella is driving down a steep hill. she should keep her car __________ to help _________.

Physics
1 answer:
Softa [21]2 years ago
8 0

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

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The velocity of the transverse waves produced by an earthquake is 5.08 km/s, while that of the longitudinal waves is 8.3312 km/s
ASHA 777 [7]

Answer:

727.67 km

Explanation:

Sine they have Same distance D

distance = speed * time

D = 5.08t

D = 8.3312(t+55.9)

so

5.08t = 8.3312(t+55.9) t in

3.2512t = 465.71

t = 143.2s

Subtitute t

D=5.08 t

= 5.08 × 143.2

= 727.67km

7 0
2 years ago
A substance that is made of atoms of more than one type bound together is called a
BigorU [14]
The substance that is made of atoms of more than one type bound together is called an atomic bond or a multi bond
6 0
3 years ago
what were two weakness of america government under the articals of confederation did the philadelphia mutiny highlight
marusya05 [52]

The weaknesses of the America government under the articals of confederation in which the Philadelphia mutiny highlighted include:

  • Inability to regulate commerce.
  • Inability to form a military.

<h3>What is a Mutiny?</h3>

This is a rebellious act among group of people in order to oppose a certain authority or government.

The government couldn't give soldiers a good working condition due to lack of funds which led to mutiny.

Read more about Mutiny here brainly.com/question/1157738

#SPJ1

4 0
2 years ago
Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The
Rudik [331]

Answer:

1)   P₁ = -2 D,   2) P₂ = 6 D

Explanation:

for this exercise in geometric optics let's use the equation of the constructor

          \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image, respectively

1) to see a distant object it must be at infinity (p = ∞)

          \frac{1}{f_1} = \frac{1}{q}

           q = f₁

2) for an object located at p = 25 cm

            \frac{1}{f_2} = \frac{1}{25} + \frac{1}{q}

We can that in the two expressions we have the distance to the image, this is the distance where it can be seen clearly in general for a normal person is q = 50 cm

we substitute in the equations

1) f₁ = -50 cm

2)  

        \frac{1}{f_2} = \frac{1}{25} + \frac{1}{50}

        \frac{1}{f_2} = 0.06

         f₂ = 16.67 cm

the expression for the power of the lenses is

          P = \frac{1}{f}

where the focal length is in meters

           

1)       P₁ = 1/0.50

        P₁ = -2 D

2)     P₂ = 1 /0.16667

        P₂ = 6 D

4 0
2 years ago
Calculate the amount of heat liberated (in kj) from 411 g of mercury when it cools from 88.0°c to 12.0°c.
Katen [24]
You should note that the melting point of mercury is -38.83°C, while the boiling point is at 356.7°C. Then, that means that there is no latent heat involved here. We only compute for the sensible heat.

ΔH = mCpΔT
The Cp of mercury is 0.14 J/g·°C
Thus,
ΔH = (411 g)(0.14 J/g·°C)(88 - 12°C)
<em>ΔH = 4,373.04 J</em>
5 0
3 years ago
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