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tia_tia [17]
2 years ago
15

Do plants have to do cellular respiration? Why or why not?

Chemistry
1 answer:
kozerog [31]2 years ago
8 0

Answer:

<h3>Plants need oxygen because plants are made living cells which need to perform cellular respiration to get the energy they need to function. Admittedly, needing to perform cellular respiration alone does not mean that consuming oxygen is required - many (micro)organisms use fermentation or anaerobic respiration.</h3>
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At a certain concentration of N2 and H2, the initial rate of reaction is 5.0 x 105 M / s. What would the initial rate of the rea
Andreyy89
I’m really sorry I need points I hope you find an answer
6 0
3 years ago
The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?
givi [52]

Explanation:

The given reaction equation is as follows.

             2A + B \rightarrow C

So, rate constants for different reactants and products written as follows.

             \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

         A = -2

         B = -1

         C = 1

Therefore,

      \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

      \frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}    

             \frac{-k_{A}}{-2} = k_{B} = k_{C}

Hence,          k_{B} = k_{C} = \frac{25}{2} (L/mol)^{2}

                                          = 12.5 (L/mol)^{2}

Thus, we can conclude that k_{B} and k_{C} are 12.5 (L/mol)^{2}.

5 0
3 years ago
What is the empirical formula for a compound that is 83.7% carbon and 16.3% hydrogen?
zubka84 [21]
Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g 
H: 16.3% = 16.3 g 

Let us use the above mentioned data (in g) and values will be ​​converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

C:  \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol

H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol

We note that the values ​​found above are not integers, so let's divide these values ​​by the smallest of them, so that the proportion is not changed, let's see:

C:  \dfrac{6.975}{6.975} = 1

H:  \dfrac{16.3}{6.975} \approx 2.3

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, t<span>hus, the minimum or empirical formula found for the compound will be:
</span>
\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark

I hope this helps. =)
8 0
3 years ago
HELP PLZ ( 10 points )
marta [7]

compressibility - is a measure of the relative volume change of a fluid or solid as a response to a pressure (or mean stress) change. (D)

Flammability - ability of a chemical to burn or ignite, causing fire or combustion. (B)

Heat of Combustion - The amount of heat released per unit mass or unit volume of a substance when the substance is completely burned. (A)

Reactivity - the state or power of being reactive or the degree to which a thing is reactive (C)

Hope this helps!!

4 0
3 years ago
Why does sodium have a lower melting point then magnesium
Lady bird [3.3K]

Answer:

Number of delocalized electrons

Explanation:

Magnesium has more delocalized electrons compared to sodium and this accounts for the higher melting point.

  • When magnesium atoms comes together to form a metallic bonds, they have more network of delocalized electrons.
  • There is more pull for the localized electrons due to the nuclear charge on the nucleus.
  • This strong intermolecular metallic bond increases the melting point of magnesium.
3 0
3 years ago
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