Answer:
Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)
Explanation:
There are three steps you must follow. You must write the:
- Molecular equation
- Ionic equation
- Net ionic equation
A. Molecular equation
BaCl₂(aq) + Na₂SO₄(aq) ⟶ BaSO₄(s) + 2NaCl(aq)
B. Ionic equation
You write all the soluble substances as ions.
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
C. Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
Ba²⁺(aq) + <u>2Cl⁻(aq) </u>+ <u>2Na⁺(aq</u>) + SO₄²⁻(aq) ⟶ BaSO₄(s) + <u>2Na⁺(aq)</u> + <u>2Cl⁻(aq)
</u>
The net ionic equation is
Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)
Ca(NO3)2 -------> Ca²⁺ +2NO3⁻
M(Ca(NO3)2)= M(Ca) + M(N) + 6M(O)= 40.0 +14.0 +6*16.0 = 150 g/mol
15.0 g Ca(NO3)2 * 1mol/150 g = 0. 100 mol Ca(NO3)2
Ca(NO3)2 -------> Ca²⁺ +2NO3⁻
1 mol 2 mol
0.100 mol 0.200 mol
We have 0.2 mol NO3⁻ in 300. mL=0.300 L of solution,
so
0.200 mol NO3⁻ / 0.300 L solution ≈ 0.667 mol NO3⁻ /L solution = 0.667 M
Concentration of NO3⁻ is 0.667 M.
<span>Answer: B. Ionic solids have higher melting points than molecular solids.
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This is because the rest are false, as solids are able to melt, and do have melting points. Also, not all solids have the same melting points.
Answer: 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water. if 124 grams of the sodium acetate dissolves in 100 milliliters of water, then 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water.
