Most of the compounds containing C and H are organic so A. CH4 is the correct option
The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
Learn more about molarity:
brainly.com/question/15370276
Answer:
Neutrons = ( Atomic mass – Atomic number ) ( A–Z )
Protons and Electrons are equal to the atomic number
For example Neon,
Mass number (A) = 20
Atomic Number (Z) = 10
Number of Protons = 10
Number of Electrons = 10
Number of Neutrons = ( A–Z ) = 10
Electronic distribution :
K= 2
L= 8
Answer: In a chemical equation the reactants are located on the left side and the products are located on the right side.
