6+2=115 and its good it took test
Answer:
V= 12mL
Explanation:
you had the right idea with your Significant figures however, when we divide we see that it requires 2 significant figures as our least amount. this is because when looking at our division, 62 has 2 sig. fig. while 5.35 has a total 3. when looking at your answer we see that you had a total of 3 sig. figures. so in actuakity you had to round up to 12 and not to the tenths because the decimal makes .6 count as your third sig fig.
0.116 V is the e value for the oxidation of cytochrome c by the cue redox center in complex iv when the ratio of cyst c (fe3 ) /cyst c (fe2 ) is 20 and the ratio of cue (cu2 )/cue (cu ) is 3.
<h3>
Explain the process of oxidation of cytochrome c.</h3>
When cytochrome c is oxidized by mitochondrial cytochrome oxidase (COX), it attaches to Apaf-1 to produce the apoptozole, which activates pro-caspase-9 and causes cell death. Cyst can be created from cytosolic cytochrome c. In the IMS, oxidized cytochrome c can scavenge superoxide without converting it into H2O2, a process that happens naturally but is accelerated by SOD. The benefit of scavenging superoxide independently of H2O2 synthesis is reducing the possibility of hydroxyl radical generation via the Fenton reaction.
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The weight/weight percent(%w/w) of NaCl in solution : 33.03%
<h3>Further explanation</h3>
Given
Mole fraction of NaCl : 0.132
Required
The weight/weight percent of NaCl
Solution
1 mol solution : 0.132 mol NaCl + 0.868 mol H₂O
mass NaCl :
mass H₂O :
Total mass = 7.714 + 15.64 = 23.354 g
Answer:
V₂ = 495.89 mL
Explanation:
Given data:
Initial number of moles = 0.213 mol
Initial volume = 652 mL
Final number of moles = 0.162 mol
Final volume = ?
Solution:
V₁/n₁ = V₂/n₂
By putting values,
652 mL/0.213 mol = V₂ /0.162 mol
V₂ = 652 mL 0.162 mol /0.213 mol
V₂ = 105.62 mL.mol /0.213 mol
V₂ = 495.89 mL
