4.7 M It may be wrong, but I hope it helps!
Explanation:
When you're diluting a solution, you're essentially keeping the number of moles of solute constant while changing the total volume of the solution.
Now, let's assume that you don't know the equation for dilution calculations.
In this case, you can use the molarity and volume of the concentrated solution to determine how many moles of hydrochloric acid you start with.
c
=
n
V
⇒
n
=
c
⋅
V
n
HCl
=
18 M
⋅
190
⋅
10
−
3
L
=
3.42 moles HCl
You then add water to get the total volume of the solution from
190 mL
to
730 mL
.
The number of moles of hydrochloric acid remains unchanged, which means that the molarity of the diluted solution will be
c
=
3.42 moles
730
⋅
10
−
3
L
=
4.7 M
Your answer is Echology.
Definetion: Echology <span>is the </span>scientific<span> analysis and study of interactions among organisms and their environment.
</span>
Answer:
percent error = - 99.134 %
Explanation:
Given data:
measured length = 1.85 cm
accepted or given value length = 2.15 m
percent error = ?
Solution:
First of all we will convert the length in meter into cm.
1 meter = 100 cm
2.15 × 100 = 215 cm
Formula:
percent error = (measured value - accepted value/ accepted value) × 100%
Now we will put the values in equation
percent error = (1.85 cm - 215 cm/ 215 cm) × 100%
percent error = -0.9914 × 100%
percent error = - 99.134 %
Answer:
For organic compounds, carbon and hydrogen are listed as the first elements in the molecular formula, and they are followed by the remaining elements in alphabetical order. For example, for butane, the molecular formula is C 4 H 10.
Explanation:
Answer: The 
of 
is 
.
Explanation:
Given: ![[Ag^{+}] = 1.3 \times 10^{-4} M](https://tex.z-dn.net/?f=%5BAg%5E%7B%2B%7D%5D%20%3D%201.3%20%5Ctimes%2010%5E%7B-4%7D%20M)
The reaction equation will be written as follows.
This shows that the concentration of 
is half the concentration of 
ion. So,
![[CrO^{2-}_{4}] = \frac{1.3 \times 10^{-4}}{2}\\= 0.65 \times 10^{-4} M](https://tex.z-dn.net/?f=%5BCrO%5E%7B2-%7D_%7B4%7D%5D%20%3D%20%5Cfrac%7B1.3%20%5Ctimes%2010%5E%7B-4%7D%7D%7B2%7D%5C%5C%3D%200.65%20%5Ctimes%2010%5E%7B-4%7D%20M)
The expression for of this reaction is as follows.
![K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5E%7B2%7D%5BCrO%5E%7B2-%7D_%7B4%7D%5D)
Substitute values into the above expression as follows.
![K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]\\= (1.3 \times 10^{-4})^{2} \times 0.65 \times 10^{-4}\\= 1.1 \times 10^{-12}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5E%7B2%7D%5BCrO%5E%7B2-%7D_%7B4%7D%5D%5C%5C%3D%20%281.3%20%5Ctimes%2010%5E%7B-4%7D%29%5E%7B2%7D%20%5Ctimes%200.65%20%5Ctimes%2010%5E%7B-4%7D%5C%5C%3D%201.1%20%5Ctimes%2010%5E%7B-12%7D)
Thus, we can conclude that the of is .
