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Nitella [24]
3 years ago
13

Charlie is balancing an equation. She has identified the atoms and counted the number of each in the reactants and products. Wha

t would Charlie adjust to make the number of atoms in the reactants the same as the number of atoms in the products?
Chemistry
2 answers:
WITCHER [35]3 years ago
6 0

Answer:

The stoichiometric coefficients.

Explanation:

Hello,

Chemical reactions are widely generalized by the following chemical equation:

aA+bB-->cC+dD

Capitalized letters are referred to both the reacting and produced species during the chemical reaction meanwhile the lowered case letters are referred to the stoichiometric coefficients which balance the chemical reaction. Balancing means that the number of atoms in the reagents must be equal to the number of atoms in the products, this is exemplified via the following balanced chemical reaction:

2HCl+Ca(OH)_2-->CaCl_2+2H_2O

The coefficient 2 in the hydrochloric acid is set due to the produced calcium chloride which has two chlorine atoms in order to equal them.

Best regards.

const2013 [10]3 years ago
4 0

Answer: Stochiometric coefficients

Explanation: The chemical equations must be balanced to follow the law of conservation of mass which says that the mass of products must be same as the mass of reactants.

CH_4+O_2\rightarrow CO_2+H_2O

This is a skeletal equation  and needs to be balanced by adjusting the stochiometric coefficients. In order to keep the mass same, the number of atoms must be same on both sides.  

CH_4+2O_2\rightarrow CO_2+2H_2O


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3 years ago
How many atoms of Lead are in a 62.7 g sample of Lead(II) permanganate?
Alexandra [31]

Answer:

\large \boxed {8.48 \times 10^{22}\text{ atoms}}

Explanation:

1 mol of Pb(MnO₄)₂contains 1 mol of Pb atoms.

1. Moles of Pb

\text{Moles of Pb} = \text{62.7 g Pb(MnO$_{4}$)}_{2} \times \dfrac{\text{1 mol Pb(MnO$_{4}$)}_{2}}{\text{445.07 g Pb(MnO$_{4}$)}_{2}}\\\\\times \dfrac{\text{1 mol Pb}}{\text{1 mol  Pb(MnO$_{4}$)}_{2}} = \text{0.1409 mol Pb}

2. Atoms of Pb

\text{Atoms of Pb} = \text{0.1409 mol Pb } \times \dfrac{ 6.022  \times 10^{23}\text{ atoms Pb }}{\text{1 mol Pb }}\\\\= \large \boxed {\mathbf{8.48 \times 10^{22}}\textbf{ atoms Pb }}

8 0
3 years ago
What is described by the amount of energy required to change a gram of a liquid to a gas at the
ehidna [41]

Answer:

Heat of vaporization.

Explanation:

the amount of energy needed to change the specific amount or gram of liquid in to gas phase is called heat of vaporization.

In this liquid is converted into gas phase as because after the boiling point addition of more energy will cause breakage of bonds present in between the liquid molecules which results in the vaporization of liquid.

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Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂

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3 years ago
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