Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer: 51,440
Step-by-step explanation:
If a Veterinary tech earns 32,490 and a Barista earns 19,630
You're gonna create the equation ( 32,490 x 4 ) and get 129,960. Then your gonna subtract ( 19,630 x 4 ) from 129,960 and get around 51,440.
Also, you get the 4 from the number of years he works, which is 4.
Answer:
36
Step-by-step explanation:
The maximum height is the y-coordinate of the vertex
given a quadratic in standard form : ax² + bx + c : a ≠ 0
then the x-coordinate of the vertex is
= - 
y = - x² + 20x - 64 is in standard form
with a = - 1, b = 20 and c = - 64, hence
= - 
= 10
substitute x = 10 into the equation for y
y = - (10)² + 20(10) - 64 = 36 ← max height
(a) The sum of length and width is half the perimeter, so the breadth in terms of length (x) in cm will be
.. breadth = 34 -x
(b) Then the expression for the area (in cm^2) is
.. area = length*breadth
.. 253 = (x)(34 -x)
.. x^2 -34x +253 = 0 . . . . . subtract the right side, eliminate parentheses
.. (x -11)(x -23) = 0 . . . . . . . factor
.. x = 11 or 23
The dimensions of the rectangle are 11 cm by 23 cm.
