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QveST [7]
1 year ago
7

The point A(−1,−8) is reflected over the point (2,−2) and its image is point B. What are the coordinates of point B?

Mathematics
1 answer:
Veseljchak [2.6K]1 year ago
7 0

The coordinates of the point B as described in which case it is the image formed upon reflection of point A is; (5,4)

<h3>What is the coordinate of the point B which is the image formed by reflection of point A?</h3>

If follows from the task content description that the point A is an initial point which upon reflection yields point B.

Hence, it follows that the coordinates of point B can be determined according as follows;

For x coordinate;

-1 -2 = 2 - x

And hence, x = 5.

For y coordinate;

-8-(-2) = -2 - y

y = 4.

Hence, the coordinates of the image point B is; (5,4).

Read more on reflection of points;

brainly.com/question/5017530

#SPJ1

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A calculator screen shows a number in scientific notation as 4.67e-8 write this number in standard form
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Answer:

467 000 000

Step-by-step explanation:

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Negative -> decimal with lots of places, Positive -> big, big number

Move the decimal place right 8 times so you end up with a small decimal.

4.67 -> 467000000

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3 years ago
HELP IS MUCH NEEDED :)
ElenaW [278]
∠ADC = 112°
∠ADC =6x + 7 + 12x - 3

Equate both:
6x + 7 + 12x - 3 = 112

Solve for x :
6x + 7 + 12x - 3 = 112

Combine like terms:
18x + 4= 112

Take away 4 from both sides:
18x = 108

Divide both sides by 18:
x = 6

Find ∠ADB:
6x + 7 = 6(6) + 7 = 43


Answer: ∠ADB = 43°

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3 years ago
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Eggs ares sold in boxes. A small box holds 6 eggs hina buys x small boxes of eggs write down in terms of x the total number of e
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3 years ago
Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.
vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}

So, it becomes,

\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ

Hence, the value of cos theta is -0.352.

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3 years ago
In your own words what would the steps be to solve by graphing.
expeople1 [14]

Answer:

Graph the first equation.

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Check the solution in both equations.

Step-by-step explanation:

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2 years ago
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