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V125BC [204]
3 years ago
10

Chemistry is the study of matter true or false

Chemistry
2 answers:
Oksi-84 [34.3K]3 years ago
5 0
I believe that the answer is true
mario62 [17]3 years ago
4 0
The answer is "True"
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Which conversion factor correctly shows the relationship between moles and representative particles?
strojnjashka [21]
This is given by Avogagro number: 1 mol = 6.02*10^23 particles

Then you can do whichever to these two relations, because they are equivalent:

- 1mol / 6.02*10^23 representative particles, and
- 6.02*10^23 representative particle /1 mol

Only the second option of the question includes one of the valid conversion factors. Then, the conversion factor of the second option is the right answer
8 0
3 years ago
. What happens the pH of an acid solution as a base is added?​
Dmitrij [34]

As a base is added to an acidic solution, the H+ ions in solution that make it acidic are slowly neutralized into water (via OH-, the base). As these ions are converted into water the concentration of them decreases, so the pH decreases, as they are directly related.

Hope this helps!

3 0
3 years ago
Which of the following procedures is used during the fractional distillation of petroleum?
dem82 [27]
Increase at the temperature
7 0
3 years ago
How can endothermic and exothermic reactions help others (society)
AnnZ [28]
Here try this presentation, it should help :) 

https://prezi.com/6ofdo3fadl9a/exothermic-and-endothermic-reactions-in-everyday-life/
4 0
4 years ago
A 72.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by a
Aliun [14]

Answer: 0.20 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.40 M

V_1 = volume of stock solution = 72.0 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = 248 ml

1.40\times 72.0=m\times 248

m=0.41M

Now 124 mL portion of this prepared solution is diluted by adding 133 mL of water.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.41 M

V_1 = volume of stock solution = 124 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = (124 +133) ml = 257 ml

0.41\times 124=m\times 257

m=0.20M

Thus the final concentration of the solution is 0.20 M.

8 0
4 years ago
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