Answer:
150m
Explanation:
The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).
So we need to compute the integral of speed over time from 0.0s to 5.0s.
The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).
The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2
distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m
Alternatively, we can use the acceleration formula:
a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2
distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.
Answer:
the net energy Gained per hour equals 30Kcal/h
D) Ride comfort, i<span>t won't let me answer unless there are 20 characters so I added this pointless sentence.</span>
Answer:
True A and B
Explanation:
Let's propose the solution of the exercise before seeing the affirmations.
We use the law of refraction
n₁ sin θ₁ = n₂. Sin θ₂
Where n₁ and n₂ are the refractive indices of the two means, θ₁ and θ₂ are the angles of incidence and refraction, respectively
sin θ₂ = (n1 / n2) sin θ₁
Let's apply this equation to the case presented. The index of refraction and airs is 1 (n1 = 1)
Sin θ₂ = (1 / n2) sin θ₁
the angle θ₂ which is the refracted angle is less than the incident angle
Let's analyze the statements time
A. False. We saw that it deviates
B. True Approaches normal (vertical axis)
C. False It deviates, but it is not parallel to normal
D. False It deviates, but approaching the normal not moving away
E. True. Because its refractive index is higher than air,
