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denis-greek [22]
3 years ago
9

Two coulombs of charge pass through a wire in 5 seconds. Calculate the current in the wire. 1​

Physics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

0.4A.

Explanation:

Current (A) = Charge (coulomb)/Time (secs)

2 coulombs/5 secs = 0.4A

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A violin string E vibrates faster then another violin string G when bowed. Which string produced a sound with higher frequency?​
Lisa [10]

Violin string E

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5 0
3 years ago
Please help me with this very easy question I just don’t get it.
diamong [38]

Answer:

150m

Explanation:

The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).

So we need to compute the integral of speed over time from 0.0s to 5.0s.

The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).

The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2

distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m

Alternatively, we can use the acceleration formula:

a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2

distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.

5 0
2 years ago
Please help me fast please help​
inysia [295]

Answer:

the net energy Gained per hour equals 30Kcal/h

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3 years ago
The development of new technology requires the evaluation of the overall benefit to cost ratio of the new technology.
Valentin [98]
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4 0
3 years ago
Read 2 more answers
A beam of light traveling in air strikes a glass slab at an angle of incidence less than 90°. After entering the glass slab, wha
ad-work [718]

Answer:

True A and B

Explanation:

Let's propose the solution of the exercise before seeing the affirmations.

We use the law of refraction

      n₁ sin θ₁ = n₂. Sin θ₂

Where n₁ and n₂ are the refractive indices of the two means, θ₁ and θ₂ are the angles of incidence and refraction, respectively

      sin θ₂ = (n1 / n2) sin θ₁

Let's apply this equation to the case presented. The index of refraction and airs is 1 (n1 = 1)

     Sin θ₂ = (1 / n2) sin θ₁

 the angle  θ₂ which is the  refracted angle is less than the incident angle

Let's analyze the statements time

A. False. We saw that it deviates

B. True Approaches normal (vertical axis)

C. False It deviates, but it is not parallel to normal

D. False It deviates, but approaching the normal not moving away

E. True. Because its refractive index is higher than air,

8 0
3 years ago
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