Answer:
Fundamental frequency= 174.5 hz
Explanation:
We know
fundamental frequency=
velocity =
mass per unit length=
=0.00427
Now calculating velocity v=
=244.3
Distance between two nodes is 0.7 m.
Plugging these values into to calculate frequency
f =
=174.5 hz
Answer:
D) 4
Explanation:
Roots of a polynomial must be factors of the last term.
In this case, the factors of 6 are +1, -1, +2, -2, +3, -3, +6, -6. The only factor that doesn't show up, given the options, is 4. This means that D is the correct answer.
Answer:
h = 9.57 seconds
Explanation:
It is given that,
Initial speed of Kalea, u = 13.7 m/s
At maximum height, v = 0
Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :




t = 1.39 s
Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

Here, a = -g


h = 9.57 meters
So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.
These forces form a force pair. Use Newton's third law, and you see that the trailer pulls back at with the same force. The answer is d.