Answer:
0.375 M
Explanation:
NaOH(aq) + HBr(aq) ------------> NaBr(aq) + H2O(l)
Concetration of acid CA= 0.250M
Concentration of base CB= ????
Volume of acid VA= 30.0mL
Volume of base VB= 20.0mL
Number of moles of acid nA= 1
Number of moles of base nB= 1
CA VA/CB VB= nA/nB
CB= CAVAnB/VB nA
= 0.25× 30×1/20×1= 0.375 M
I do not believe you're asking this...
OK. Sulfur has a total of 24 isotopes. Every isotope has 16 protons and the number of neutrons ranges from 10 to 33 inclusive.
Phosphorus has a total of 23 isotopes. They have 15 protons, and between 9 and 31 neutrons inclusive. So here we go.
S-49
S-48
S-47, P-46
S-46, P-45
S-45, P-44
S-44, P-43
S-43, P-42
S-42, P-41
S-41, P-40
S-40, P-39
S-39, P-38
S-38, P-37
S-37, P-36
S-36, P-35
S-35, P-34
S-34, P-33
S-33, P-32
S-32, P-31
S-31, P-30
S-30, P-29
S-29, P-28
S-28, P-27
S-27, P-26
S-26, P-25
P-24
If you're looking for STABLE isotopes, then the list is much smaller.
S-36
S-34
S-33
S-32, P-31
When mixing substances, in order to find the final temperature after mixing, it is important to remember that the energy released should be equal to the energy absorbed by the system. We calculate as follows:
Q1 = Q2
(mCΔT)1 = (mCΔT)2
100 ( 90 - T ) = 50 ( T - 10 )
T = 63.33 °C
Here are the given:
<span>ΔHf° = –423 kJ/mol
</span> ΔHsub = 119 kJ/mol
IE = 469 kJ/mol
ΔHEA = –301 kJ/mol
BE = 161 kJ/mol
The lattice energy of the compound is solved using the formula:
U = <span>ΔHf° - </span>ΔHsub - BE - IE - ΔHEA
U = -423 - 119 - 161 - 469 - (-301)
U = -871 kJ/mol
Therefore, the lattice energy is 871 kJ/mol (released).
