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mihalych1998 [28]
2 years ago
7

What method of heat transfer occurs when your skin feels hot outside on a sunny, summer day?

Chemistry
2 answers:
Stolb23 [73]2 years ago
4 0

Answer:

i checked it again it's B

Explanation:

radiation sorry

slavikrds [6]2 years ago
3 0

Answer:

B. Radiation

Explanation:

Lol this weekend I got a rlly bad sunburn and ik a lot ab the sun

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Is Sun the biggest planet?
seropon [69]

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Rays used to take pictures of bones in the human body are:
Alexeev081 [22]

Answer:

B

Explanation:

Because when you go to the doctors they say, "You need to get your x-rays done" not microwave

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3 years ago
1. Calculate the energy change (q) of the surroundings (water) using the enthalpy equation
Rasek [7]

Answer:

Q1: 728.6 J.

Q2:

a) 668.8 J.

b) 0.3495 J/g°C.

Explanation:

<em>Q1: Calculate the energy change (q) of the surroundings (water) using the enthalpy equation:</em>

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(24.9 mL) = 24.9 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 32.2°C - 25.2°C = 7.0°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (24.9 g)(4.18 J/g°C)(7.0°C) = 728.6 J.

<em>Q2:  Calculate the energy change (q) of the surroundings (water) using the enthalpy equation </em>

<em>qwater = m × c × ΔT.  </em>

<em>We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation.</em>

<em></em>

a) First part: the energy change (q) of the surroundings (water):

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(25 mL) = 25 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 31.6°C - 25.2°C = 6.4°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (25 g)(4.18 J/g°C)(6.4°C) = <em>668.8 J.</em>

<em>b) second part:</em>

<em>Q water = Q unknown metal. </em>

<em>Q unknown metal =  - </em>668.8 J. (negative sign due to the heat is released from the metal to the surrounding water).

<em>Q unknown metal =  - </em>668.8 J = m.c.ΔT.

m = 27.776 g, c = ??? J/g°C, ΔT = (final T - initial T = 31.6°C - 100.5°C = - 68.9°C).

<em>- </em>668.8 J = m.c.ΔT = (27.776 g)(c)( - 68.9°C) = - 1914 c.

∴ c = (<em>- </em>668.8)/(- 1914) = 0.3495 J/g°C.

<em></em>

3 0
3 years ago
The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
Elena-2011 [213]

Answer:

20 atm / (R . 321 K . i) = M

Explanation:

Osmotic pressure is a colligative property which is determined by the solute.

Solutes over solutions, can increase the osmotic pressure which is calculated like this:

P = M . R . T

where P is pressure, M is molarity, R the Universal Constant Gases and T, the absolute Temperature. We also have to consider the Van't Hoff factor, i, numbers of ions dissolved. Ionic salts determine more osmotic pressure than organic compounds, where i = 1. Then, the complete formula is:

π =  M . R . T . i

To determine molarity, osmotic pressure divide all the terms:

20 atm / (R . 321 K . i) = M

R = 0.082 L.atm/mol.K

If you see all the units in R, they will be cancelled, so finally the answer will be mol/L, which is molarity. The i term has no unit!.

4 0
2 years ago
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