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Butoxors [25]
2 years ago
9

What is the molarity of a solution that contains 50.0g of NaOH (molar mass = 40 grams/mole) in 2.0L of solution?

Chemistry
2 answers:
Oksi-84 [34.3K]2 years ago
4 0
It is 39.997 molarity
weeeeeb [17]2 years ago
3 0
39.997
hope this helps
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Which molecule is polar, based on structure? 1) sulfur dioxide 2) carbon disulphide 3) ethylene 4) carbon tetrachloride
Savatey [412]
I think the correct answer from the choices listed above is option 1. It would be the molecule carbon disulphide that will be polar, based on the structure of the choices given. Hope this answers the question. Have a nice day. Feel free to ask more questions.
4 0
3 years ago
Read 2 more answers
Which of the following is not an example of a chemical change? (hint:
Lena [83]

Answer:

C. Boiling water

Explanation:

Boiling water is a physical change only; the H20 molecules are moving from a liquid state to a gas state and not turning into a new substance.

3 0
3 years ago
PLEASE HELP!!!!!<br><br> Calcium hydroxide is _____.<br><br> an acid<br> a base<br> a neutral
Bingel [31]
I believe it is a base!
4 0
2 years ago
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Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2
love history [14]

Answer:

<u>Option 1</u>:  N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²    

Explanation:

<u>Ionic radius is the radius of an atom´s ion in ionic crystal structure</u>.<u> </u><u><em>In an ion that lose an electron, to form a cation, the radius of the ion gets smaller</em></u><em>, </em>because the repulsion between electrons decrease because fewer electrons are present. Conversely, <u><em>adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.</em></u>                  

<u><em>Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers</em></u>.                        

<u><em>In a isolelectronic series (same number of electrons),</em></u> <u><em>the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius </em></u>beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.  

<u>We will use this principle to solve our problem</u>.  

In our case, the given ions are:  

  • N⁻³ :    Z = 7,  e⁻ = 10
  • O⁻²:     Z= 8,   e⁻ =10
  • F⁻:       Z = 9,  e⁻ = 10
  • Na⁺:    Z= 11,   e⁻ = 10
  • Mg⁺²:  Z=12,   e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

<em><u>Hence the decreasing order of ionic radius is:</u></em>

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²  

Have a nice day!

4 0
3 years ago
Suppose a system returns to its original overall, internal energy ((∆U) after the following changes. In step 1, 25 J of work is
Brums [2.3K]

Answer:

Heat transfer in step 2 = 47.75 J

Explanation:

Internal energy = heat + work done

U = Q + W

In a cyclic process the total internal energy change of the system = 0.

In the process there are two steps. The total heat exchange in the process is the sum of heat exchanges in the two processes.

We have to find the heat exchange in step 2.

In step 1,

W = 1.25 J          Q = -37 J

U_{1} = -37 + 1.25 = -35.75 J

In step 2, the internal energy change will be negative of that in step 1.

U = 35.75 J

W = -12 J

U = Q + W

35.75 = Q -12

Q = 47.75 J

Heat transfer in step 2 = 47.75 J

6 0
3 years ago
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