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finlep [7]
2 years ago
12

Consider the following voltaic cell:(d) At which electrode are electrons consumed?

Chemistry
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0

Electrons are consumed at the cathode.

Cathode

the cathode is referred to as the electrode where reduction takes place. In an electrochemical cell, this is typical. Here, the cathode is negative because the cell's electrical energy supply causes chemical molecules to break down. It can, however, also be advantageous, as in a galvanic cell, where a chemical reaction results in the production of electrical energy.

A cathode is often referred to as a hot cathode or a cold cathode. A hot cathode is one that has been heated by a filament in order to emit electrons by thermionic emission, as opposed to a cold cathode, which has not been heated by a filament. If a cathode emits more electrons than those produced by thermionic emission alone, it is typically labeled as "cold."

Learn more about cathode here:-

brainly.com/question/19261112

#SPJ4

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Identify and name the global<br> wind belts.<br> A<br> B<br> C<br> D<br> E<br> F<br> G
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8 0
2 years ago
A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C・g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('
polet [3.4K]

Answer:

a=5.65cm

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

Q_{Pt}=-Q_{Deu}

We can represent the heats in terms of mass, heat capacities and temperatures:

m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})

Thus, we solve for the mass of platinum:

m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g

Next, by using the density of platinum we compute the volume:

V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3

Which computed in terms of the edge length is:

V=a^3

Therefore, the edge length turns out:

a=\sqrt[3]{180cm^3}\\ \\a=5.65cm

Best regards.

6 0
3 years ago
How many moles of hydrogen do you need to react with 0.85 moles of nitrogen?
katen-ka-za [31]

Answer:

6 moles

Explanation:

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8 0
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