From Carnot's theorem, for any engine working between these two temperatures:
efficiency <= (1-tc/th) * 100
Given: tc = 300k (from question assuming it is not 5300 as it seems)
For a, th = 900k, efficiency = (1-300/900) = 70%
For b, th = 500k, efficiency = (1-300/500) = 40%
For c, th = 375k, efficiency = (1-300/375) = 20%
Hence in case of a and b, efficiency claimed is lesser than efficiency calculated, which is valid case and in case of c, however efficiency claimed is greater which is invalid.
i think the answer is D 10.0
Answer:
XL sleep usual Addison officer at home and ear is not a short time to be be free and ear is a short time to make a short time
Explanation:
so that I can take the class on Monday and ear is not a short time to be be free and ear is not a short time to be be free and ear is not a short time to be be free and ear is not a short time to time for a day or night and ear buds is Anshu and duster and duster fgor a day or night is Anshu and duster for a day or not a week of computer science from your computer and I am in the same as I am a short of ti and you can be the first time I will be be
Voltage of each component is same.
Answer:
0.615 m
Explanation:
We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.
The acceleration is determined using the equation of motion.
Given parameters:
Initial velocity, <em>u</em> = 0.00 m/s
Distance, <em>s</em> = 4.19 m
Time, <em>t</em> = 0.601 s
We use the equation

With <em>u</em> = 0.00 m/s,



The force is

From Hooke's law, the extension, <em>e</em>, of a string is given by

where <em>k</em> is the spring constant.
Hence,
