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Karo-lina-s [1.5K]
3 years ago
9

Rupert (66 kg) is now in a full-pipe of radius 25 m, calculate the minimum speed at which Rupert can skate to ensure he will not

a fall off the skateboard at the top of the pipe?
**SHOW WORK**
Physics
1 answer:
V125BC [204]3 years ago
4 0

at the top most point if Rupert will not fall then normal force at the top point is almost zero for minimum speed

so here we can say

F_n + mg = m\frac{v^2}{R}

now if

F_n = 0

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = \sqrt{25 \times 9.8}

v = 15.65 m/s

so above will be the minimum speed

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3 0
3 years ago
Assume that the force exerted on each crutch by the ground is directed along the crutch, as the force vectors in the drawing ind
olya-2409 [2.1K]

Answer: 43 degrees

Explanation:

The force of the crutch can be broken into components.  The horizontal component of F is the static friction force keeping the crutch from sliding.  The vertical component is opposing the weight and is the Normal force.  Using the orientation of the angle q, we have the following

fs = Fx = F sin (angle (tita))

N = Fy = F cos (angle(tita))

Maximum angle implies maximum static friction

Therefore,

fsmax = UsN = Us x F cos(angle tita)

Where U = miyu

F sin(angle tita) = Us x Fcos (angle tita)

Sin (angle tita) / cos (angle tita) = Us

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Angle tita = tan^-1(Us) = tan^-1 (0.931) = 42.95 degrees = 43 degrees

There for Angle tita Max = 43 degrees

7 0
3 years ago
An atom is.......Help?
Dmitry_Shevchenko [17]
The smallest level of ordination in living things. Every living thing is made up of atoms. Atoms are made up of protons, neutrons, and electrons.
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Which group of elements are shiny, opaque, and have a high melting point?
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1. thomas jefferson proposed using the length (l) of a simple pendulum whose period (t) was exactly 2 seconds as the definition
Alecsey [184]

The length of a 2 sec pendulum is 1 m.

Given that, initial length of the simple pendulum L₁ = 1 m

Initial time period T₁ = 2 sec

We need to find the length of the pendulum whose time period is 2 sec

T₂ = 2 sec

L₂ = ?

We know that the time period of the simple pendulum is given by the formula,

T = 2π√(L/g)

From the above relation, we can write T ∝ √L

T₁ / T₂ = √(L₁/L₂)

Making L₂ from the above relation, we have,

L₂ = (T₂² * L₁)/ T₁² = 2² * 1/ 2² = 1 m

Thus, the length of a 2 sec pendulum is 1 m.

To know more about time period:

brainly.com/question/17350379

#SPJ4

7 0
1 year ago
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