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Elden [556K]
3 years ago
8

How many excess electrons are on a ball with a charge of -1.4944 10-16 C?

Physics
1 answer:
agasfer [191]3 years ago
7 0

Answer:

There are 934 excess electrons on the ball with charge -1.4944*10^(-16).

Step-by-Step Explanation:

A ball will usually be neutral and have no charge on it.

If it is negatively charged, it means there are excess electrons on it.

If we know the charge on the ball, we can count the excess no. of electrons.

We know that the charge on the ball = c = -1.4944*10^-16

Charge of one electron = e = 1.6*10^-19

Charge of n electrons on the ball = ne = c

⇒ n = c/e

n = (-1.4944*10^-16)/(1.6*10^-19)

n = 934 electrons

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C. A helium atom has a diameter of approximately 9.8 • 10-11 meters. What is the diameter of a helium atom in nanometers? Given
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1\ nm = 10^{-9} m\\\\1\ m =\frac{1\ nm}{10^{-9}}

Since the diameter of helium atom is approximately 9.8\times 10^{-11}\ m, therefore the diameter of helium atom in nano meter,

9.8\times 10^{-11}\ m=9.8\times 10^{-11} \times\frac{1\ nm}{10^{-9}}=0.098\ nm

4 0
3 years ago
3, A 4kg block is pushed 2m at an acceleration of 0.2m/s square up a vertical wall by a constant force F applied at an angle of
Andrews [41]

The work done by the applied force on the block against the frictional force is 15.75 J.

<h3>Work done by the applied force</h3>

The work done by the applied force is calculated as follows;

W = Fd

F - Ff = ma

where;

  • F is applied force
  • Ff is frictional force

Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

0.799F - 7.077 = 0.8

F = 9.86 N

W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

Learn more about work done here: brainly.com/question/25573309

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5 0
2 years ago
Write short notes on:<br>human made wetland​
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Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.

<h3>What is a human-made wetland​ ?</h3>

Any kind of wetland that has been created or kept up by people for purposes like water storage, irrigation, or aquaculture.

In India's Punjab state, in the Kapurthala district, lies the man-made Kanji Wetland, which includes the Kanji Lake.

In order to give irrigation facilities to the hinterland, it was built by building the headworks over the perennial Bien River, a tributary of the Beas River.

The Sunderbans are India's biggest wetland. The world's biggest mangrove forest includes Sunderban Wetland.

Hence, the human-made wetland​ is an artificial wetland.

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4 0
2 years ago
A circular loop ( radius = 0.5 m) carries a current of 3.0 A and has unit normal vector of (2i - j +2k)/3 what is x component of
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Answer:

T=9.42Nm

Explanation:

From the question we are told that:

Radius r= 0.5 m

Current I= 3.0 A

Normal vector n=\frac{(2i - j +2k)}{3}

Magnetic field B= (2i-6j) T

Generally the equation for Area is mathematically given by

 A=\pi r^2

 A=3.1415 *0.5^2

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Generally the equation for Torque is mathematically given by

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Where

 i'*B= \begin{bmatrix}2&-1&2\\2&-6&0\end{bmatrix}

 X\ component\ of\ i'*B= [(-1 * 0)-(2*-6)]

 X\ component\ of\ i'*B=12

Therefore

 T=0.7853*12

 T=9.42Nm

7 0
3 years ago
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