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ioda
2 years ago
7

Devise an experiment using a Landsat satellite and hypothesize results.

Physics
1 answer:
guapka [62]2 years ago
8 0

An experiment that involves using a Landsat satellite is given below;

Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in  cape town, South Africa.

<h3>What is the experiment about?</h3>

Rice is known to be one of the most vital  food staples in a lot of countries, especially South Africa . Due to the irrigated rice production that tend to  differs from other kinds of  agricultural fields, this study was said to have created a paddy field mapping model via the use of  phenological aspects, a lot of  satellite sensor data, and also the use of object-based approach.

This study  uses the phonological features of rice plants and also the use of an annual data regarding surface temperature (LST) to make the paddy map.

The core remote sensing data is made up of the yearly LST that is obtained from MODIS and multi-temporal Landsat-8 satellite imagery.

Based on the study, the total  accuracy and kappa coefficient for the pixel-based classification method is seen to be  92% and 0.89.

Hence, An experiment that involves using a Landsat satellite is Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in  cape town, South Africa.

Learn more about Landsat satellite from

brainly.com/question/25656875

#SPJ1

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Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b.  h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

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F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

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So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² =  (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² =  √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

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