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masya89 [10]
3 years ago
7

What is the magnitude of the resultant vector? Round your answer to the nearest tenth.

Physics
2 answers:
zimovet [89]3 years ago
5 0

Answer:

13.9

YOUR WELCOME

Vesna [10]3 years ago
3 0

R = √ (5²m² + 13²m²)

R = √ (25m² + 169m²)

R = √194m²

R = 13.928... m

<em>R = 13.9 m</em>

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The graphs show the motion of an object in both the x and y directions. Classify the motion of this object.
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B It is moving in one dimension

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An atom of element X has one more shell of electrons than an atom of beryllium, but it has one less valence electron than beryll
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The correct answer is Sodium
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If light moves at a speed of 299,792,458 m/s, how long will it take light to move a distance of 1,000 km
astra-53 [7]

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change 1000km into Metre

1000km=1000000 M

speed= distance/time

time=distance/speed

time=1000000/299792458

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Which object will sink in freshwater, which has a density of 1.0 g/cm3?
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On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

3 0
3 years ago
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