The answer for this question would be B) False or the second option because top-down processing is NOT often used when one encounters an unfamiliar stimulus.
The refrigerator's coefficient of performance is 6.
The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.
As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.
The heat produced in the cold compartment, H = 780.0 J
Work done in ideal refrigerator, W = 130.0 J
Refrigerator's coefficient of performance = H/W
= 780/130
= 6
Therefore, the refrigerator's coefficient of performance is 6.
Energy conservation requires the exhaust heat to be = 780 + 130
= 910 J
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The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.
<h3>What is current?</h3>
The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
For the given set of parallel resistors, we need to find the resistance of each resistor.
From the Ohm's law, V =IR
R = V/I
Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.
Thus, the student D gives enough evidence to find resistance of the circuit is
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Answer:
nope don't think so
Explanation:
the heat causes the molecules to move faster therefore expanding in watever it the air is in
Answer:
Explanation:
Let the angle between the first polariser and the second polariser axis is θ.
By using of law of Malus
(a)
Let the intensity of light coming out from the first polariser is I'
.... (1)
Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.
By the law of Malus

So,



(b)
Now differentiate with respect to θ.

