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Rudik [331]
4 years ago
15

A machine part rotates at an angular speed of 0.76 rad/s; its speed is then increased to 2.96 rad/s using an angular acceleratio

n of 1 rad/s 2 . Find the angle through which the part rotates before reaching this final speed. Answer in units of rad.
Physics
1 answer:
son4ous [18]4 years ago
5 0

Answer:

θ = 4.092 °

Explanation:

Given that

Initial Angular speed ,ωi = 0.76 rad/s

Final angular speed ,ωf= 2.96 rad/s

The angular acceleration ,α = 1 rad/s²

We know that

ωf² = ωi ²+ 2 α θ

θ=Angle rotates

2.96² = 0.76²+ 2 x 1 x θ

\theta=\dfrac{2.96^2-0.76^2}{2}\ degrees\\\theta=4.092\ degrees\\

Therefore the angle rotates by machine part will be 4.092 degrees.

θ = 4.092 °

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lara [203]

Time taken by the bowling ball to reach its highest point= 0.214 s

initial velocity= Vi=2.1 m/s

Final velocity= Vf=0 as the velocity at the highest point is zero.

acceleration= g= -9.8 m/s²

using the kinematic equation Vf= Vi + at

0= 2.1 + (-9.8)t

t= -2.1/-9.8

t=0.214 s

Thus the time taken by the bowling ball to reach its highest point is 0.214 s

6 0
3 years ago
How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the
KATRIN_1 [288]

Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

7 0
3 years ago
The distance vs. time graph of a car moving at constant speed should be a straight line. Why do the data points in the graph plo
iragen [17]

Answer:

The measurements are inexact

Explanation:

6 0
3 years ago
Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said
ra1l [238]

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

'f'

Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

7 0
3 years ago
Two objects, one having three times the mass of the other, are dropped from the same height in a vacuum. At the end of their fal
gogolik [260]

Answer:

Two objects will have the equal velocities but the forces on both of them will not be equal. The equal velocities of these objects are due to their equal acceleration.

Explanation:

From the newton's equation

v^{2} -u^{2} = 2as

so here we can say that velocity does not depends on the mass.

The acceleration of both objects will be same but not the forces because

F = Ma

As the force is depending on the mass so it will not be the same for both objects.

5 0
3 years ago
Read 2 more answers
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