Please can i have help with this question
1 answer:
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<h2>
</h2><h3>kinetic energy is given as</h3>
KE = (0.5) m v²
given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg
KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J
when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J
when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J
when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J
Answer:
V=28.5m/s
b=V=28.5m/s
c=V=28.5m/s
Explanation:
A slingshot fires a pebble from the top of a building at a speed of 15.0 m/s. The building is 30.0 m tall. Ignoring air resistance, find the speed with which the pebble strikes the ground when the pebble is fired.
(a) horizontally,
(b) vertically straight up,
(c) vertically straight down.
u=15m/s
yi=30m
v=?
yf=0
system=pebble+earth
workdone=0
chnage in energy=0
ki+Ui=Kf+Ui
K=kinetic energy
U=potential energy
1/2mv^2+mgyf=1/2mu^2+mgyi
V^2=u^2+2gyi
V=
V=28.5m/s
b. and c will be the same as a. because the magnitude of the kinetic energy is dependent on the velocity and not the magnitude which the pebble is tilted at