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2 years ago

applying an electric current to the x-ray tube causes electrons to be boiled off the filament, producing x-rays. true false

1 answer:

8 0

According to the research, the correct option is true. Applying an electric current to the x-ray tube causes electrons to be boiled off the filament, producing x-rays.

This is the part of the equipment that generates the X-rays, which consists of the electrons being accelerated to energies of 30 to 150 keV and hitting a tungsten target producing X-rays.

Specifically, it contains the cathode and the anode, which is covered by a protective and insulating casing, where the electrons emitted by a filament in the cathode reach the anode strongly accelerated, generating X-ray emission as a consequence, being the basis of all devices using ionizing radiation.

Therefore, we can conclude that according to the research, the correct option is true. Applying an electric current to the x-ray tube causes electrons to be boiled off the filament, producing x-rays.

Learn more about x-ray tube here: brainly.com/question/15274343

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A cannon is mounted on a cart which sits on the ground, supported by frictionless wheels. The mass of the cannon and cart is 4.6

Kitty [74]

Answer:

The velocity of the launcher after the projectile is launched is -5.011 m/s

Explanation:

Here we have the mass of the cannon and cart, m₁ = 4.65 kg

Velocity of cannon and cart, v₁ = 2.00 m/s

Mass of projectile, m₂ = 50.0 g = 0.05 kg

Velocity of projectile, v₂ = 647 m/s

Velocity of the launcher, v₃ = Required

Mass of cannon and cart, launcher after launching projectile m₃ = 4.65-0.05

= 4.6 kg

Therefore, from the principle of the conservation of linear momentum, we have

Total initial momentum = Total final momentum

m₁ × v₁ = m₂ × v₂ + m₃ × v₃

Substituting gives

4.65 kg × 2.00 m/s = 0.05 kg × 647 m/s + 4.6 kg × v₃

4.65 kg × 2.00 m/s - 0.05 kg × 647 m/s = 4.6 kg × v₃

-23.05 kg·m/s = 4.6 kg × v₃

$v_3 = \frac{-23.05 \, kg\cdot m/s}{4.6 \, kg} = \frac{-461}{92} m/s$

v₃ = -5.011 m/s.

3 0

3 years ago

Read 2 more answers

Operators must slow to no wake speed when within what distance of a u.s. naval vessel?

Alex Ar [27]

Recreational boaters have a role in keeping the waterways safe and secure. Violators of the restrictions can expect a quick and severe response. The operator should not approach within yards and slow to minimum speed within 500 yards of any of united states naval vessel. If the vessel need to pass within 100 yards of a united states naval vessel for safe passage, must contact the united states naval vessel or the united states coast guard escort vessel on VHF-FM channel 16. In addition,

• The operator must perceive and avoid all security areas.

• Avoid commercial port operation areas particularly those that include military cruise line or petroleum amenities.

• The operator must perceive and avoid other controlled areas near dams, power plants, etc.

• The operator of the vessel must not discontinue or anchor underneath bridges or in the channel.

6 0

3 years ago

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Your bedroom gets direct sunlight through a window during the hottest part of the day. You ask your mom to turn down the thermom

ycow [4]

I want to say its cooled by reflection because of the foil, sun reflects off of the foil back into the atmosphere. I don't think it's conduction because I have the foil on my windows and it's never warm to the touch. it's not a liquid so I don't believe it's convection. The foil reflects the radiation so I don't think it's b, c or d. so I wanna say A but I'm not 100% sure

6 0

3 years ago

What is the average acceleration of the particle between 0 seconds and 4 seconds? A. 0 meters/second2 B. 0.04 meters/second2 C.

lisov135 [29]

Answer

D. 0.25 meters/second2

Explanation

The average acceleration is the ratio of change in velocity to the change in time of travel.Taking in this case that the change of velocity is a unit, then Average acceleration is given by;

Aacc=Vf-Vi/Tf-Ti

where Vf=final velocity,Vi=initial velocity' Tf=final time, Ti=initial time

Vf-Vi=1m/s

Tf-Ti=4-0=4seconds

Avacc=1/4=0.25m/s2

6 0

3 years ago

A 1200.0-kg car is traveling at 19m/s. The driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic f

Alja [10]

<h2>Answer</h2>

option D)

2.4 seconds

<h2>Explanation</h2>

Given in the question,

mass of car = 1200kg

speed of car = 19m/s

Force due to direction of travel

F = ma

= 12000(a)

Force to due frictional force in reverse direction

-F = mg(friction coefficient)

= -12000(9.81)(0.8)

<h2>-mg(friction coefficient) = ma </h2>

(cancelling mass from both side of equation)

g(0.8) = a

(9.81)(0.8) = a

a = 7.848 m/s²

<h2>Use Newton Law of motion</h2><h3>vf - vo = a • t</h3>

where vf = final velocity

vo = initial velocity

a = acceleration

t = time

0 - 19 = 7.8(t)

t = 19/7.8

= 2.436 s

≈ 2.4s

5 0

3 years ago