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Fantom [35]
3 years ago
8

An electron in a mercury atom drops from energy level f to energy level c by emitting a photon having an energy of

Physics
2 answers:
arlik [135]3 years ago
6 0

Answer: it’s 2

Explanation: you can find the answer on the physics reference sheet

Julli [10]3 years ago
5 0

Answer:

The answer is 2.84 eV

Explanation:

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A sphere with a radius of 15 cm rolls on a level surface with a constant angular speed of 10 rad/s. To what height on a 30° incl
Scrat [10]

Explanation:

Below is an attachment containing the solution.

8 0
3 years ago
The particle accelerator at CERN can accelerate an electron through a potential
asambeis [7]

Answer:

K.E = 1.28 × 10^-17 KeV

Explanation:

Given that a particle accelerator at CERN can accelerate an electron through a potentialdifference of 80 kilovolts.

To Calculate the kinetic energy (in keV) of the electron​, let us first find the electron charge which is 1.60 × 10^-19C

The kinetic energy = work done

K.E = e × kV

Substitute e and the voltage into the formula

K.E = 1.60 × 10^-19 × 80

K.E = 1.28 × 10^-17 KeV

Therefore, the kinetic energy is approximately equal to 1.28 × 10^-17 KeV

8 0
3 years ago
What two things does light provide?
labwork [276]

Answer:

Light provides brightness to see and also light carries energy

5 0
3 years ago
A roller-coaster car moves 172 ft horizontally and then rises 115 ft at an angle of 31.0° above the horizontal. it next travels
lianna [129]

172 + 115 cos 31 +115 cos 48 horizontally

115 sin 31 - 115 sin 48  vertically

possibly need some drawing

4 0
3 years ago
If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.
Anna35 [415]

This question is incomplete

Complete Question

Three equal point charges are held in place as shown in the figure below

If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.

A) F1=2F2

B) F1=3F2

C) F1=4F2

D) F1=9F2

Answer:

D) F1=9F2

Explanation:

We are told in the question that there are three equal point charges.

q, Q1, Q2 ,

q = Q1 = Q2

From the diagram we see the distance between the points d

q to Q1 = d

Q1 to Q2 = nd

Assuming n = 2

= 2 × d = 2d

Sum of the two distances = d + 2d = 3d

F1 is the force on q due to Q1 and

F2 is the force on q due to Q2,

Since we have 3 equal point charges and a total sum of distance which is 3d

Hence,

F1 = 9F2

6 0
4 years ago
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