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Katyanochek1 [597]
4 years ago
15

If a person whirls an object horizontally in a counter clockwise direction and the string breaks at point P as shown, what path

will the rock follow?

Physics
2 answers:
Nata [24]4 years ago
4 0

when an object is revolving in circular path then its velocity is always along the tangent of the circular path

so while moving in circular path if the string is break then due to law of inertia the object will always move in the direction of initial motion

As we know that as per law of inertia if an object will not change its state of motion or state of rest until some external force will act on it.

So here also the object will move along its tangential direction once the string will break

so here the correct path will be

Option B

igomit [66]4 years ago
3 0

Position B is the path that the rock will follow.

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Brant pushes a toy car with a force of 50 N. The force of friction as the car moves is 5 N. What is the net force on the car?
ICE Princess25 [194]

net force= the sum of all the forces acting on the object

the frictional force is opposite to the direction of motion of the object

If the object moves to the right (positive) then the friction force moves to the left (negative).

so the net force: 50 N - 5 N = 45 N (B)

4 0
3 years ago
Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

7 0
4 years ago
From 0 seconds to 4 seconds is the acceleration positive or negative?
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Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0
4 years ago
The thermal efficiency of a power cycle operating in a reversible manner is found to be 50%. Assuming that the same 2 thermal re
inna [77]

Answer:

Explanation:

The thermal efficiency of a Power cycle \eta = \dfrac{Q_H -Q_c}{Q_H}

where;

\eta = 50\% = 0.5

Q_H = Heat \ flow \ from \ higher \ temperature

Q_c = Heat \ flow \ from \ lower \ temperature

0.5 = \dfrac{Q_H -Q_c}{Q_H}

0.5 Q_H = Q_H - Q_c --- (1)

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The coefficient of performance is:

COP_R = \dfrac{Q_c}{Q_H -Q_c}

let replace the value of Q_c = 0.5 Q_H   in the above equation then;

COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}

COP_R = \dfrac{0.5Q_H}{0.5 Q_H}

COP_R = 1

The

On the other hand,  the heat pump

COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}

By replacing equation (1) into the above equation; we have:

COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}

COP_{HP} = \dfrac{1}{0.5}

COP_{HP} =2

t

5 0
3 years ago
1.
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Answer:

different sample have different properties is not a characteristics of a compound ,

Explanation:

because compound will always same properties no matter how quantity is

6 0
3 years ago
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