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Naily [24]
3 years ago
12

How are surface temperature and length of year on a planet related to the planet’s distance from the Sun?

Physics
1 answer:
Artist 52 [7]3 years ago
8 0
The farther from the sun an object is the larger the distance a planet has to orbit the sun. So if a planet is far from the sun the years would be longer. And if a planet is close to the sun it would be much hotter than a planet that is far from the sun.
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Help me with this review question please.
QveST [7]

Answer:

K E=( mv²)/2

=(60×3.5²)/2

=367.5J

6 0
2 years ago
For crystal diffraction experiments, wavelengths on the order of 0.25 nm are often appropriate.
Kamila [148]

Answer:

A) E = 4.96 x 10³ eV

B) E = 4.19 x 10⁴ eV

C) E = 3.73 x 10⁹ eV

Explanation:

A)

For photon energy is given as:

E = hv

E = \frac{hc}{\lambda}

where,

E = energy of photon = ?

h = 6.625 x 10⁻³⁴ J.s

λ = wavelength = 0.25 nm = 0.25 x 10⁻⁹ m

Therefore,

E = \frac{(6.625 x 10^{-34} J.s)(3 x 10^8 m/s)}{0.25 x 10^{-9} m}

E = (7.95 x 10^{-16} J)(\frac{1 eV}{1.6 x 10^{-19} J})

<u>E = 4.96 x 10³ eV</u>

<u></u>

B)

The energy of a particle at rest is given as:

E = m_{0}c^2

where,

E = Energy of electron = ?

m₀ = rest mass of electron = 9.1 x 10⁻³¹ kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

E = (9.1 x 10^{-31} kg)(3  x  10^8 m/s)^2\\

E = (8.19 x 10^{-14} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\

<u>E = 4.19 x 10⁴ eV</u>

<u></u>

C)

The energy of a particle at rest is given as:

E = m_{0}c^2

where,

E = Energy of alpha particle = ?

m₀ = rest mass of alpha particle = 6.64 x 10⁻²⁷ kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

E = (6.64 x 10^{-27} kg)(3  x  10^8 m/s)^2\\

E = (5.97 x 10^{-10} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\

<u>E = 3.73 x 10⁹ eV</u>

8 0
2 years ago
What happens if you are riding your bike and hit something (like a curb) with the front wheel
evablogger [386]
You would flip forward or to the side
6 0
3 years ago
At what minimum speed must a roller coaster be traveling when upside down at the top of a circle so that the passengers do not f
worty [1.4K]

Answer:

v_{min} \approx 17.153\,\frac{m}{s}

Explanation:

The roller coaster begins with maximum kinetic energy and no gravitational potential energy. The gravitational potential energy reaches its maximum when roller coaster is upside down at the top of the circle. The physical model for the roller coaster is constructed by means of the Principle of Energy Conservation:

\frac{1}{2}\cdot m \cdot v_{min}^{2} = m\cdot g \cdot h

The minimum velocity is:

v_{min} = \sqrt{2\cdot g \cdot h}

Let assume that radio of curvature is measured in meters. Hence:

v_{min} = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot(15\,m)}

v_{min} \approx 17.153\,\frac{m}{s}

8 0
2 years ago
Dos láminas, una de cobre y otra de hierro, se encuentran soldadas y empotradas enuna pared como lo muestra la figura 13. Si las
PolarNik [594]

Answer:

umm i gotta put this in English!!!!!

7 0
3 years ago
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