Answer:
the average induced emf in the second winding is
Explanation:
The magnetic field inside the first solenoid is given by,
Where is the permeability of the free space
N is the number of turns of solenoid per unit length
I is the current in the solenoid
A is the cross-sectional area of the wire
Replacing we have,
Thus average emf induced in the second windigs is,
Therefore the average induced emf in the second winding is
Answer:
40 km/h
Explanation:
First...
Look at the formula speed is equal to the distance over time or s = d/t.
Next...
Use the formula: 240/6.0
Finally...
Solve: 40
So the answer: 40 km/h
I think it is (3) 690 N. You can use the theorem of Impulse and momentum where the impulse is equal to the change in momentum or:
(where f is for final and i for initial).
So you get:
Answer:
The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.
2.0 kg into the bifactor of 1/4 so the mass struck would be 32