Two tuning forks having frequencies of 460 and 464 Hz are struck simultaneously. What average frequency will you hear, and what
1 answer:
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Answer:
2.1406 × m/sec
Explanation:
we know that energy is always conserved
so from the law of energy conservation
here V is the potential difference
we know that mass of proton = 1.67× kg
we have given speed =50000m/sec
so potential difference
now mass of electron =9.11×
so for electron
so the velocity of electron will be 2.1406× m/sec
To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.
We know that by Hooke's law
Where,
k = Spring constant
x = Displacement
Re-arrange to find k,
Perioricity in an elastic body is defined by
Where,
m = Mass
k = Spring constant
Therefore the period of the oscillations is 0.685s