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2 years ago

11

Two tuning forks having frequencies of 460 and 464 Hz are struck simultaneously. What average frequency will you hear, and what

will the beat frequency be

1 answer:

Inessa [10]2 years ago

7 0

Answer:

462Hz, 4Hz

Explanation:

The average frequency heard would be 462 Hz because that is the average between the two and we do not hear one note more than another so the average is 462 Hz. (460+464)/2 = 462Hz. The beat frequency is basically the difference between frequencies, so our beat frequency is 464-460=4Hz.

Hope this helped!

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eimsori [14]

E=(mV^2)/2
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vesna_86 [32]

Answer:

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Explanation:

As we know that the density is the ratio of mass and volume

here we know that

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3 years ago

What is the pressure drop due to the Bernoulli Effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire

Marianna [84]

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Explanation:

Given that,

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$P_{1}+\dfrac{1}{2}\rho v_{1}^2=P_{2}+\dfrac{1}{2}\rho v_{2}^2$ ....(I)

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$v_{1}=\dfrac{Q}{A_{1}}$

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$v_{2}=6.28\ m/s$

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(b). We need to calculate the maximum height

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$\Delta P=\rho g h$

Put the value into the formula

$1.58\times10^{6}=1000\times9.8\times h$

$h=\dfrac{1.58\times10^{6}}{1000\times9.8}$

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8 0

3 years ago

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BartSMP [9]

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