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2 years ago

What is the angular momentum at a radius of 2 m with an object of 5 kg at a velocity of 20 m/s?

Physics

2 answers:

aev [14]2 years ago

5 0

The angular momentum is 200 kg m^2 s^-1

<h3>what is angular momentum?</h3>

Angular momentum is the product of linear momentum and the perpendicular distance. Linear momentum is the product of mass and velocity, where radius is the perpendicular distance

Angular momentum = mass * velocity * radius

Angular momentum = 5 * 2 * 20

Angular momentum = 200 kg m^2 s^-1

read more about angular momentum here: brainly.com/question/4126751

ahrayia [7]2 years ago

3 0

Answer:

200

Explanation:

angular momentum=mvr

=2×5×20

= 200kgm2/s

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Master of physics needed

Delicious77 [7]

Hey JayDilla, I get 1/3. Here's how:
Kinetic energy due to linear motion is:
$E_{linear}= \frac{1}{2}mv^2$
where
$v=r \omega$
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$E_{linear}= \frac{1}{2}mr^2 \omega ^2$

The rotational part requires the moment of inertia of a solid cylinder
$I_{cyl} = \frac{1}{2}mr^2$
Then the rotational kinetic energy is
$E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2$
Adding the two types of energy and factoring out common terms gives
$\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})$
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part. Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

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GenaCL600 [577]

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