The rock has a height <em>y</em> at time <em>t</em> according to
<em>y</em> = 25 m + (60 m/s) sin(32°) <em>t</em> - 1/2 <em>gt</em> ²
where <em>g</em> = 9.8 m/s² is the magnitude of the acceleration due to gravity.
Solve for <em>t</em> when <em>y</em> = 0. The quickest way to do this is with the quadratic formula.
0 = 25 m + (60 m/s) sin(32°) <em>t</em> - 1/2 <em>gt</em> ²
<em>t</em> = (-(60 m/s) sin(32°) + √[(60 m/s)² sin²(32°) - 4 (25 m) (-1/2 <em>gt</em> ²)]) / 2
(ignoring the negative root because that would make <em>t</em> negative)
or approximately
<em>t</em> ≈ 7.2 s
REALISM shows things as they REALLY look.
It was super heated to turn in to a liquid
Answer:
v=3.66,h-3.66
Explanation:
vertical = 10sin60 - 10sin 30
horizontal =10cos60 + 10cos 30
v = 10×0.8660-10×0.5
h = 10×0.5 + 10 × 0.8660
v=8.660-5.0 = 3.66
h= 5.0-8.660 = -3.66
Answer:
150A
Explanation:
Given parameters:
Potential difference = 120V
Resistance = 0.8Ω
Unknown:
Current = ?
Solution:
From ohm's law;
I =
I is the current
V is the voltage
R is the resistance
Now insert the parameters and solve;
I = = 150A