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Nikitich [7]
2 years ago
10

What is the angular momentum at a radius of 2 m with an object of 5 kg at a velocity of 20 m/s?

Physics
2 answers:
aev [14]2 years ago
5 0

The angular momentum is 200 kg m^2 s^-1

<h3>what is angular momentum?</h3>

Angular momentum is the product of  linear momentum and the perpendicular distance. Linear momentum is the product of mass and velocity, where radius is the perpendicular distance

Angular momentum = mass * velocity * radius

Angular momentum = 5 * 2 * 20

Angular momentum = 200 kg m^2 s^-1

read more about angular momentum here: brainly.com/question/4126751

ahrayia [7]2 years ago
3 0

Answer:

200

Explanation:

angular momentum=mvr

=2×5×20

= 200kgm2/s

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Explanation:

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time taken b y car = 12.6 sec

v-u=at

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8 0
2 years ago
a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the
tatuchka [14]
The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
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the force of the wind F, acting horizontally, with intensity
F=12 N
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
T \cos \alpha -F=0
T \sin \alpha -W=
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By replacing this value into the first equation, we can also find the tension of the rope:
T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N




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3 years ago
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Blababa [14]
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I hope my answer helped you out! :)

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Answer:

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