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3 years ago

What is domain theory? How does it explain how an electromagnet become magnetic

Physics

1 answer:

tresset_1 [31]3 years ago

8 0

A magnet has two poles that is called north and sound the only information I can give

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How does radioactive decay work

Lesechka [4]

Answer:

Radioactive decay is the spontaneous breakdown of an atomic nucleus resulting in the release of energy and matter from the nucleus. Remember that a radioisotope has unstable nuclei that does not have enough binding energy to hold the nucleus together.

Explanation:

6 0

3 years ago

Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. T

diamong [38]

Answer:

Rate of heat is 45.1 kJ/min

Explanation:

Heat required to evaporate the water is given by

Q = mL

here we know that

$L = 2.25 \times 10^6 J/kg$

now we have

$Q = (0.200)(2.25 \times 10^6 J/kg)$

$Q = 452.1 kJ$

now the power is defined as rate of energy

$P = \frac{Q}{t}$

$P = \frac{452.1 kJ}{10}$

$P = 45.1 kJ/min$

6 0

3 years ago

Imagine a place in the cosmos far from all gravitational and frictional influences. Suppose that you visit that place (just supp

xz_007 [3.2K]

The rock will continue to travel in a straight line with a constant velocity for ever... The reason is, once it leaves your hand there is no force acting on the rock, so it will just continue to move in a natural motion which is constant velocity.

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3 years ago

Which data set has the largest range?

likoan [24]

Answer:

ummm there is nothing attached :(

Explanation:

3 0

2 years ago

Read 2 more answers

RP 1 - Specific Heat Capacity GCSE Exam Questions (B.S.G)

Stels [109]

When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.

A sample of 0.50 kg of water boils (reaches 100 °C). After a while, its temperature decreases by 22 °C.

We can calculate the energy transferred to the surroundings from the water in the form of heat (Q) using the following expression.

$Q = c \times m \times \Delta T = \frac{4200J}{kg.\° C} \times 0.50kg \times (-22\° C) \times \frac{1kJ}{1000J} = -46.2 kJ$

where,

c: specific heat capacity of water
m: mass of water
ΔT: change in the temperature

When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.

Learn more: brainly.com/question/16104165

8 0

2 years ago