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Charra [1.4K]
3 years ago
13

As velocity increases, what happens to momentum?

Physics
2 answers:
ss7ja [257]3 years ago
6 0

Answer:

B. it increases

Explanation:

Remember that momentum = mass * velocity. So momentum and velocity are directly proportional, so as velocity increases, so will momentum of the object.

Anna007 [38]3 years ago
5 0

Answer:

If velocity of an object increases then moment would also get increased.

Explanation:

Velocity and mass are directly proportional to momentum.

hope it helps!

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Hydrogen is found in three different states inside Jupiter, ______, liquid, and liquid ______.
tekilochka [14]

Answer:

gas, metal

Explanation:

The three states of by which hydrogen is found in Jupiter is made up of:

  1. Gaseous hydrogen
  2. liquid hydrogen
  3. liquid metal hydrogen

This is also the same states found in Saturn too.

The pressure inside the largest planet in our solar system is very great.

  • Hydrogen and helium makes up the entirety of the planet Jupiter.
  • It has been discovered that inside this planet, hydrogen often occurs as gas, liquid and metal
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Which simple machine belongs to the inclined plane family
Vlad [161]
The wedge and screw simple machines
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When measuring espresso for a drink, which instrument would give the<br> greatest precision?
Gemiola [76]

How many mL is an espresso?

One shot of espresso is generally about 30–50 ml (1–1.75 oz), and contains about 63 mg of caffeine (3). Important point: The “golden ratio” for espresso is this: a single shot is 30 to 44 mL (1 to 1.5 ounces) of water and 7 grams of coffee

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3 years ago
In the voltage multiplier experiment, why not use a zener diode?​
Svet_ta [14]

Answer:

<em>A voltage multiplier is an electrical circuit that converts AC electrical power from a lower voltage to a higher DC voltage, typically using a network of capacitors and diodes.</em>

6 0
2 years ago
A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywher
Scilla [17]

Answer:

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

Explanation:

The Coulomb's Law gives the force by the charges:

\vec{F} = K\frac{q_1q_2}{r^2}\^r

Let us denote the positon of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

F_1 = K\frac{Qq}{x^2 + y^2}\\F_1_x = F_1\cos(\theta)

where Θ is the angle between F_1 and x-axis.

F_1_x = K\frac{Qq}{x^2 + y^2}(\frac{x}{\sqrt{x^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

whereas

F_2_x = K\frac{-Qq}{a^2 + y^2}(-\frac{a}{\sqrt{a^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

Finally, the x-component of the net force is

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

8 0
3 years ago
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