4 years ago

Could anyone help with this

1 answer:

4 0

The answer is "B) Most species names are written in Swedish because Linnaeus was Swedish." Actually most if not all names in the Modern System of Taxonomic Classification are in Latin.

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384,400 in scientific notation can be written as 3.844×10^5

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Atom* the particles are (Electrons)

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A passenger walks from one side of a ferry to the other as it approaches a dock.Passenger's velocity is 1.55 m/s due north relat

victus00 [196]

Answer: $\theta =33.22^{\circ}$

Explanation:

Given

Velocity of Passenger w.r.t to Ferry

$v_{pf}=v_p-v_f=1.55\hat{j}$ -------1

Velocity of Passenger w.r.t to water

$v_{pw}=v_p-v_w=4.5\left ( -\hat{i}+\hat{j}\right )$ --------2

Subtract 2 from 1

$v_f-v_w=-4.5\hat{i}+2.95\hat{j}$

(b)direction

$tan\theta =\frac{2.95}{4.5}=0.655$

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4 years ago

A circular loop of wire is in the plane of the paper. The south pole of a bar magnet is being moved from a position in front of

drek231 [11]

Answer:

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3 years ago

A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is reese (enr647) – HS OnRamps 04

icang [17]

Answer:

W = 0 J

Explanation:

It is given that,

Weight of the crate, W = 100 N

Distance moved by the crate, d = 1.5 m

Let W is the work done to hold the crate 1.5 m above the ground in this way. It is given by the product of force and the displacement. Its formula is given by :

$W=F\times d\times cos\theta$

Here, $\theta=90^{\circ}$ as it is lifted vertically

$W=100\ N\times 1.5\ m\ cos(90)$

W = 0

So, the work done to hold the crate is 0. Hence, this is the required solution.

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3 years ago

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