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2 years ago

Use integers to represent the values in the statement.

Mathematics

1 answer:

Artyom0805 [142]2 years ago

4 0

Answer-

The mountain has an altitude of 14,316 feet. This means that the integer that represents the mountains height is 14,316. An integer is a whole number, which means that our answer is the whole amount of the height of the mountain. This question may seem tricky but we are already given our answer.

I also think that your question may not fully be answered so if it was to compare the two numbers. The peak of the mountain sits 14,613 feet tall than the bottom of the valley.

If you just need the integer ignore the second paragraph, but the mountain is 14,316 feet.

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Find the measure of KM¯¯¯¯¯¯¯¯¯¯.

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

(whole secant) x (external part) = (whole secant) x (external part)

( 7+x+2) * 7 = ( 6+8) * 6

Combine like terms

(9+x) *7 = 14*6

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63 +7x = 84

Subtract 63

63 +7x -63 = 84-63

7x =21

Divide by 7

7x/7 = 21/7

x = 3

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= 3+2+7

=12

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3 years ago

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Given that 1/3 of a box is 6 dollars, we can say that per dollar is 1/18 of a box. If you have 4 dollars, this would mean that you can buy 4/18 of a box to 2/9 of a box. Hope this answers your question. Have a great day ahead!

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3 years ago

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A study of 12,000 able-bodied male students at the University of Illinois found that their times for the mile run were approxima

den301095 [7]

Answer:

$P (y < 6) = \frac{P(y- \mu)}{\sigma} \mu}{\sigma} \\\\=P(z$

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618

Step-by-step explanation:

Normal with mean 6.88 minutes and

a standard deviation of 0.57 minutes.

Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)

$\mu = 6.88$

$\sigma = 0.57$

y ≈ normal (μ, σ)

The z score is the value decreased by the mean divided by the standard deviation

$P (y < 6) = \frac{P(y- \mu)}{\sigma} \mu}{\sigma} \\\\=P(z$

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618

3 0

3 years ago

How do you solve this?

zaharov [31]

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3 years ago

Does (0,0) satisfy x+3y>3

PtichkaEL [24]

$\bf x+3y > 3\qquad \qquad (\stackrel{x}{0}~~,~~\stackrel{y}{0})\qquad \qquad 0+3(0) > 3\implies \stackrel{\stackrel{\textit{is this true?}}{\downarrow }}{0>3}\qquad nope!$

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3 years ago