Question

when dropped from rest, any object will fall a total distance of 19.6 m in the first 2 seconds of its fall. how far does the object fall just during the 2nd second (i.e., from time t

Answer 1

The object fall just during the 2nd second is 14.7m.

As we know the equation of motion

equation off motion are equation that describe the behavior of physical system in terms of its motion as a function of time.

using 2nd equation of motion

S = ut +gt²/2

S= distance covered

u = initial velocity

g = acceleration due to gravity

t = time taken (t= 1 sec)

a = g = 9.8 m/s²

u = 0 m/s

At time t=1 sec

S₁ = 0 + 9.8 (1)²/2  = 4.9m

S₁  = 4.9m

S1 is the distance covered in ist second.

At t = time (t= 2 sec)

S₂ = 0 + 9.8 (2)²/2  = 19.6m

S₂ = 19.6m

S2 is the distance covered after 2nd second.

The object fall just during the 2nd second is

S = S₂ - S₁

S = 19.6 - 4.9  = 14.7m

The object fall just during the 2nd second is 14.7m.

To know more about equation of motion :

brainly.com/question/22719691

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