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2 years ago

Which option contains a correct statement about the size of

Chemistry

1 answer:

Vinil7 [7]2 years ago

5 0

Answer:

a molecule always has two or more atoms

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What is vaccine (question answer)

Ket [755]

Above answer is correct

6 0

3 years ago

What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid =

laiz [17]

What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid = 1.8 x 10-5)?

[KOH] = 0.65 M
[OH] = 0.65 M
Dilute your mom
[OH]Dil= 0.65 M * 70/80 = 0.56875 M

pH = 5.4

7 0

3 years ago

A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 3.5 × 10-4 M in calcium ion and 2.33

Burka [1]

Answer:

B. A precipitate will form since Q > Ksp for calcium oxalate

Explanation:

Ksp of CaC₂O₄ is:

CaC₂O₄(s) ⇄ Ca²⁺ + C₂O₄²⁻

Where Ksp is defined as the product of concentrations of Ca²⁺ and C₂O₄²⁻ in equilibrium:

Ksp = [Ca²⁺][C₂O₄²⁻] = 2.27x10⁻⁹

In the solution, the concentration of calcium ion is 3.5x10⁻⁴M and concentration of oxalate ion is 2.33x10⁻⁴M.

Replacing in Ksp formula:

[3.5x10⁻⁴M][2.33x10⁻⁴M] = 8.155x10⁻⁸. This value is reaction quotient, Q.

If Q is higher than Ksp, the ions will produce the precipitate CaC₂O₄ until [Ca²⁺][C₂O₄²⁻] = Ksp.

Thus, right answer is:

B. A precipitate will form since Q > Ksp for calcium oxalate

4 0

3 years ago

PLEASE HELP

morpeh [17]

conductor because it conducts the electrons

6 0

3 years ago

Read 2 more answers

Nault 25000L 250 our = 25000L 15040 8. How many grams of CaCl2 are needed to make 150.0 mL of a 0.500 M CF solution? (Note: CaCl

yuradex [85]

Answer:

You need 8,324 g of CaCl₂ yo make this solution

Explanation:

Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.

To know the grams of CaCl₂ it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:

0,1500 L × $\frac{0,500 mol}{L}$ = 0,075 CaCl₂ moles

Now, with the molar mass of CaCl₂ you will obtain the necessary grams, thus:

0,075 CaCl₂ moles × $\frac{110,98 g}{mol}$ = 8,324 g of CaCl₂

So, you need 8,324 g of CaCl₂ to make 150,0 mL of a 0,500M solution

I hope it helps!

3 0

3 years ago