Hello there.
<span>How many particles are in a mole?
Answer: </span><span>6.022</span>
Answer:
— 159.6°C
Explanation:
Data obtained from the question include:
V1 (initial volume) = 960L
T1 (initial temperature) = 38°C = 38 + 273 = 311K
V2 (final volume) = 350L
T2 (final temperature) =?
Since the pressure is constant, then Charles' law is in operation. Using the Charles' law equation V1/T1 = V2/T2, we can easily obtain the final temperature as follow:
V1/T1 = V2/T2
960/311 = 350/T2
Cross multiply to express in linear form.
960 x T2 = 311 x 350
Divide both side by 960
T2 = (311 x 350) /960
T2 = 113.4K
Now let us convert 113.4K to a number in celsius scale. This is illustrated below:
°C = K — 273
°C = 113.4 — 273
°C = — 159.6°C
Therefore, the container will have a volume of 350L at — 159.6°C
20 calories equals to 8.368 joules.
4.184 J is needed to raise 1 gram of water.(Heat capacity of water)
for 2 grams of water 8.368 joules.
So the answer is 16 c.
Answer:
see picture
Explanation:
see picture above. character filling moment
