What structures join with the cell's membrane during exocytosis

How many moles of calcium chloride, cacl2, can be added to 1.5 l of 0.020 m potassium sulfate, k2so4, before a precipitate is ex

Brut [27]

When CaSO4 → Ca2+ + SO4
So when we have Ksp = [Ca2+][SO4]

when Ksp = 4.93 x 10^-5
and [SO4] = 0.02 M
so by substitution we can get [Ca2+]
4.93x10^-5 = [Ca2+] [0.02]
∴ [Ca2+] = 0.0025 mol/L

∴ the moles of calcium chloride = 0.0025 mol / L * 1.5 L
= 0.00167 mol

4 0

3 years ago

use the periodic table to select the element from the drop-down menu that has the correct relative electronegativity.

Bumek [7]

You need to list the elements but remember that fluorine has the highest electronegativity out of the entire periodic table

6 0

3 years ago

Read 2 more answers

What is DNA? What information does it carry? Where is DNA located?

zaharov [31]

Answer:

Dna is a molecule. It carries hereditary information. It is located in the chromosomes.

3 0

3 years ago

CARBOHYDRATES are found primarily in plant-based foods and are a major source of energy in the body (4 kcals per gram). If you c

SVETLANKA909090 [29]

Answer:

The 200 grams of carbohydrate would this convert to 800 kcals in a day.

Explanation:

Carbohydrates are the source of energy. The metabolism of 1 gram of carbohydrates gives 4 kcals of energy.

If 200 grams of carbohydrate is consumed in a day, then the energy provided by it is:-

$Energy\ provided\ by\ the\ carbohydrate = 200\times 4\ kcals=800\ kcals$

<u>The 200 grams of carbohydrate would this convert to 800 kcals in a day.</u>

4 0

3 years ago

Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo

Arada [10]

Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

$100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}$

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

$100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}$

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

$100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}$

3 0

3 years ago