The width of the playroom is 4 m
<h2>The atomic mass of silicon is 28.0855</h2>
Answer:
So, the evaporating pressure of the R410A = 118 psig
Explanation:
Solution:
For R410A system:
Data Given:
Evaporator Outlet Temperature = 50°F
Evaporator Superheat = 10°F
Required:
Evaporating Pressure in the system = ?
For this, first of all, we need to calculate inlet temperature on R410A system from the given value of outlet temperature.
Evaporator inlet temperature is the difference of outlet temperature and evaporator superheat.
Evaporator inlet temperature = Outlet Temperature - Evaporator Superheat
Evaporator inlet Temperature = 50°F - 10°F
Evaporator inlet Temperature = 40°F
Now, as we have the inlet temperature and the R410A system. We can consult the pressure temperature chart or PT chart, which I have attached and highlighted the value of evaporating pressure for 40°F inlet temperature.
So, the evaporating pressure of the R410A = 118 psig
When a gas is compressed rapidly, temperature increases because temperature and volume of gas are inversely proportional to each other according to gas laws. When a gas is compressed rapidly, its volume decreases leading to increase in temperature.
Also the pressure increase which also increases the randomness of the gas molecules which start to collide more frequently and thus the temperature rises .
just to make you understand what randomness affects - you would have noticed that you often sweat in a small room filled with people but it’s cooler if the same number of people are there in a bigger room.
hope it helps you