All categories

3 years ago

_______ or radioactive substance have a half life.

Physics

1 answer:

madam [21]3 years ago

4 0

Answer:

A radioactive element or radioactive substance have a half life

Explanation:

The half life of a radioactive element is defined as the time taken for the atoms of the radioactive elements to decay to half the original number

Radioactive decay

Radioactive decay simply the process by which the nucleus of a heavy radioactive element disintegrates and emits alpha or beta particles along with Gama rays

Law of radioactivity

The law states that when a radio active element decays or disintegrates it forms a new element two places below in the periodic table with emission of alpha particles or two places above the element in the periodic table with emission of beta particle.

You might be interested in

Which type of spacecraft would best be used to study the long-term effects of life in space on humans?

SVETLANKA909090 [29]

The best choice would be satellite

4 0

2 years ago

Read 2 more answers

The constant forces F1 = 8 + 29 + 32 N and F2 = 48 - 59 - 22 N act together on a particle during a displacement from the point A

steposvetlana [31]

Answer:

- 600 J

Explanation:

A (20, 15, 0 ) m

B (0, 0, 7) m

$\overrightarrow{F_{1}}=8\widehat{i}+29\widehat{j}+32\widehat{k}$

$\overrightarrow{F_{2}}=48\widehat{i}-59\widehat{j}-22\widehat{k}$

Net force

$\overrightarrow{F}=\overrightarrow{F_{1}}+\overrightarrow{F_{2}}$

$\overrightarrow{F}}=\left ( 8+48 \right )\widehat{i}+\left ( 29-59 \right )\widehat{j}+\left ( 32-22 \right )\widehat{k}$

$\overrightarrow{F}}=56\widehat{i}-30\widehat{j}+10\widehat{k}$

$\overrightarrow{S}=\overrightarrow{OB}-\overrightarrow{OA}$

$\overrightarrow{S}=\left ( 0-20 \right )\widehat{i}+\left ( 0-15 \right )\widehat{j}+\left ( 7-0 \right )\widehat{k}$

$\overrightarrow{S}=-20\widehat{i}-15\widehat{j}+7\widehat{k}$

Work done is defined as

$W = \overrightarrow{F}.\overrightarrow{S}$

$W = \left ( 56\widehat{i}-30\widehat{j}+10\widehat{k} \right ).\left (-20\widehat{i}-15\widehat{j}+7\widehat{k} \right )$

W = -1120 + 450 + 70

W = - 600 J

3 0

3 years ago

Find the speed vfinal of the joined cars after the collision. mastering physics

Tanya [424]

<span>Px = 0 Py = 2mV second, Px = mVcosĎ† Py = â€“mVsinĎ† add the components Rx = mVcosĎ† Ry = 2mV â€“ mVsinĎ† Magnitude of R = âš(RxÂ˛ + RyÂ˛) = âš((mVcosĎ†)Â˛ + (2mV â€“ mVsinĎ†)Â˛) and speed is R/3m = (1/3m)âš((mVcosĎ†)Â˛ + (2mV â€“ mVsinĎ†)Â˛) simplifying Vf = (1/3m)âš((mVcosĎ†)Â˛ + (2mV â€“ mVsinĎ†)Â˛) Vf = (1/3)âš((VcosĎ†)Â˛ + (2V â€“ VsinĎ†)Â˛) Vf = (V/3)âš((cosĎ†)Â˛ + (2 â€“ sinĎ†)Â˛) Vf = (V/3)âš((cosÂ˛Ď†) + (4 â€“ 2sinĎ† + sinÂ˛Ď†)) Vf = (V/3)âš(cosÂ˛Ď†) + (4 â€“ 2sinĎ† + sinÂ˛Ď†)) using the identity sinÂ˛(Ď)+cosÂ˛(Ď) = 1 Vf = (V/3)âš1 + 4 â€“ 2sinĎ†) Vf = (V/3)âš(5 â€“ 2sinĎ†)</span>

6 0

4 years ago

( Just answer 1 & 2) Please help! This is the last thing I have to do. I will mark brainliest asap!!

natima [27]

Answer:

1. Formula = distance/time

D= 112.0 meters, time =4 secs

Speed = d/t =112.0/4

= 28m/s

2.Formula = distance/time

D= 1/4 x 16093.44 m

= 402.35m

Time = 15secs

Speed= d/t

= 402.35/15

=26m/s

7 0

3 years ago

two cars collide with each other, before the collision one car ( m=1000 kg) is going north at 20m/s and the other car (m=1200 kg

kow [346]

Answer:

Momentum of system after collision, p = 10,000 kg-m/s

Explanation:

It is given that,

Mass of car one, m₁ = 1000 kg

Mass of second car, m₂ = 1200 kg

The first car is going towards north and second car is going towards south.

Velocity of car one, v₁ = +20 m/s (towards north)

Velocity of second car, v₂ = - 25 m/s (towards south)

As the momentum remains conserved. So, initial momentum is equal to the final momentum. So,

$p_i=p_f=m_1v_1+m_2v_2$

$p_f=1000\times 20+1200\times (-25)$

$p_f=-10,000\ kg-m/s$

Hence, after collision the momentum of the system will be 10,000 kg-m/s

7 0

3 years ago

Read 2 more answers