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irakobra [83]
2 years ago
14

NO LINKS!!!!!! Help its urgent, PLEASE HELP!!!!!!!!!!!!!!!!

Physics
1 answer:
Likurg_2 [28]2 years ago
7 0

Answer:

I think ur answer would be B

Explanation:

srry if wrong

hope this helps

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Mesopotamians also were the first to use ___________.
rusak2 [61]
I think it may be c i learned about this last year
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2 years ago
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The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u
irinina [24]

Explanation :

The forces acting on hot- air balloon are:

Weight, (W)

Force due to air resistance, (F)

Upthrust force, (U)

Its weight W is acting in downward direction. The upthrust force U acts in upward direction. When the balloon is moving upward, the air resistance is in downward and vice versa.

In this case, the hot-air balloon descends vertically at constant speed.

so, a=0

and F=ma=0

so, W = F + U ....................(1)

when it is ascending let the weight that it is releasing is R, so

(W-R) + F = U..........(2)

solving equation (1) and (2)

(W-R)+F=W-F

R=2F            

2F is the weight of material that must be released from the balloon so that it ascends vertically at the same constant speed.

7 0
3 years ago
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You connect five identical resistors in series to a battery whose EMF is 12.0 V and whose internal resistance is negligible. You
neonofarm [45]

Answer:

Explanation:

Total resistance in the circuit

= EMF / current in the circuit

= 12 / .969

= 12.383 ohm

This resistance consists of 5 identical resistances in series

resistance of each resistor

= 12.383 / 5

= 2.476 ohm .

potential difference on each

= current x resistance of each

= .969 x 2.476

= 2.399 V

= 2.4 V

4 0
3 years ago
A sharp raises a note by
vivado [14]

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8 0
3 years ago
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A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
denpristay [2]

Answer:

The mass of the rule is 56.41 g  

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

Apply principle of moment

(200 g)(22 cm - 0)     = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

3 0
3 years ago
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