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Phoenix [80]
2 years ago
13

explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th

an an unknown gas. determine the molar mass of the unknown gas. show your work or explain your answer, giving specific values used to determine the answer.
Chemistry
1 answer:
Musya8 [376]2 years ago
3 0

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

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The sodium isotope with 13 neutrons. Express your answer as an isotope
wariber [46]

Answer:

          \large\boxed{\large\boxed{^{24}_{11}Na}}

Explanation:

The question is asking to write the <em>isotopic symbol </em>of the form ^A_ZX for the <em>sodium isotope with 13 neutrons</em>.

In general, the isotopic symbol in the given form shows:

  • The element's chemical symbol: X

  • A: mass number of the isotope, written as a superscript to the left of the element's simbol, and

        A = number of protons + number of neutrons

  • Z: atomic number of the isotope, written as a subscript to the left of the elements's symbol,

        Z = number of protons

The atomic symbol of sodium is Na.

The atomic number, or number of protons, is the same for every isotope of the element, and you can find it in any periodic table. Tha atomic number of sodium is 11. Thus:

  • Z = 11

The mass number is the number of protons plus neutrons, hence:

  • A = 11 + 13 = 24

Now you can write the isotope symbol for the sodium isotope with 13 neutrons:

         ^{24}_{11}Na

6 0
4 years ago
Which of the following is part of the molarity equation?
Zinaida [17]
Answer:

Moles of Solution
4 0
2 years ago
Isopropyl alcohol is mixed with water to produce a 32.0 % (v/v) alcohol solution. How many milliliters of each component are pre
Sonja [21]

<u>Answer:</u> The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

<u>Explanation:</u>

We are given:

32.0 % (v/v) alcohol solution

This means that 32 mL of isopropyl alcohol is present in 100 mL of solution

Volume of water = 100 - 32 = 68 mL

Volume of solution given = 795 mL

Applying unitary method:

In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL

So, in 795 mL of solution, the volume of isopropyl alcohol present will be = \frac{32}{100}\times 795=254.4mL

Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL

Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

4 0
4 years ago
if 980 KJ of energy are added to 6.2 L of water at 291 K, what will the final temperature of the water be
uranmaximum [27]

Answer:

The final temperature of the water will  be 328.81 K .

Explanation:

Using the equation, <em>q = mcΔT</em>

here, <em>q = energy</em>

<em>m= mass</em>

<em>c= specific heat capacity </em>

<em>ΔT= change in temperature</em>

<em>Mass of water = 1kg (1000 g ) per liter</em>

<em>∴ 6.2 Liter of water = 6200 g</em>

<em>c of water ≈ 4.18 J /g/K</em>

<em>Now, </em>

<em>980000 = 6200*4.18*ΔT</em>

<em>ΔT = 37.81 K</em>

<em>∴ final temperature of the water = 291 + 37.81 = 328.81 K</em>

6 0
3 years ago
How many 20 mL extractions of organic solvent are needed to extract at least 99.5% of 50.0 g Compound A from 100 mL of water if
sammy [17]

Answer:

5 extractions to extract at least 99.5% of 50.0 g Compound A from 100 mL of water

Explanation:

<em>If K=10...</em>

<em />

Partition coefficient is defined as the ratio of concentrations of a compound A in two inmiscibles solvents:

K = 10 = Conc. Organic solvent / Conc. Water

<em>Usually organic phase over aqueous phase.</em>

<em />

In the first 20mL extraction, the organic solvent will extract:

10 = X / 20mL / (50.0g - X) / 100mL

10 = 100X / (1000-20X)

10000 - 200X = 100X

10000 = 300X

X = 33.3g of compound A are extracted in the first extraction

<em>Remember you want to extract 99.5%, that is 50.0g*99.5% = 49.75g</em>

<em />

In the aqueous phase remain: 50-33.3g = 16.7g:

<em>Second extraction:</em>

10 = X / 20mL / (16.7g - X) / 100mL

10 = 100X / (334-20X)

3340 - 200X = 100X

3340 = 300X

11.1g are extracted and will remain: 16.7g - 11.1g = 5.6g

<em>Third extraction:</em>

10 = X / 20mL / (5.6g - X) / 100mL

10 = 100X / (112-20X)

1120 - 200X = 100X

1120 = 300X

3.8g are extracted and will remain: 5.6g - 3.8g = 1.8g

<em>Fourth extraction:</em>

10 = X / 20mL / (1.8g - X) / 100mL

10 = 100X / (36-20X)

360 - 200X = 100X

360 = 300X

1.2g are extracted and will remain: 1.8g -1.2g =  0.6g

<em>Fifth extraction:</em>

10 = X / 20mL / (0.6g - X) / 100mL

10 = 100X / (12-20X)

120 - 200X = 100X

120 = 300X

0.4g are extracted. The total extractions gives:

33.3g + 11.1g + 3.8g + 1.2g + 0.4g = 49.8g

That means, you need to do:

<h3>5 extractions to extract at least 99.5% of 50.0 g Compound A from 100 mL of water</h3>
3 0
3 years ago
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