Answer is although the question should have 3 significant figures.
<h3>What is
significant figures?</h3>
Fe + CuSO4 --> Cu + FeSO4
It is already balanced
1 mol Fe : 1 mol CuSO4 : 1 mol Cu : 1 mol FeSO4
- atomic masses of Fe and Cu
Fe: 55.8 g/mol
Cu: 63.5 g/mol
number of moles = mass in grams / atomic mass = 93.7 g / 55.8 g/mol = 1.679 mol
1 mol Fe / 1 mol Cu => 1.679 mol Fe / 1.679 mole Cu
- mass of Cu in 1.679 moles Cu
mass = atomic mass * number of atoms = 63.5 g/mol * 1.679 moles = 106.6 g = 107 rounded to 3 significant figures.
To learn more about significant figures, refer to:
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This is how you convert gallons to liters.
- Gallon is a volumetric unit.
- 1 gallon equals 3.785 liters
- So, you create this conversion factor: 1 gal = 3.785 liter ⇒ 1 = 3.785 liter / 1 gallon.
- Therefore, you can multiply any amount in gallons by the conversion factor and get the equivalent amoun in liters.
- Examples:
- 1 gallon = 1 gallon × 3.785 liter / gallon = 3.785 liter
- 3 gallon = 3 gallon × 3.785 liter / gallon = 11.355 liter
- 15.25 gallon = 14.25 gallon × 3.785 liter / gallon = 53.936 liter
Answer:
the molarity of cobalt(II) fluoride in the resulting solution is = 0.137 M
Explanation:
Given that :
a student dissolves 6.64 g of CoF₂ into 500 mL of water
volume of the solution(water) = 500 mL = 0.50 L
The standard molar mass of CoF₂ is 96.93 g/mol
number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂
number of moles of CoF₂ = 6.64 g/96.93 g/mol
number of moles of CoF₂ = 0.0685 mol
The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.
Thus ;
Molarity of cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)
Molarity of cobalt(II) fluoride CoF₂ = 0.0685 mol/ 0.50 L
= 0.137 M
Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137 M
Answer:
I don't even know I'm sorry
