Question

explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster than an unknown gas. determine the molar mass of the unknown gas. show your work or explain your answer, giving specific values used to determine the answer.

Answer 1

The molar mass of the unknown gas is 184.96 g/mol

Graham's law of diffusion

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

How to determine the molar mass of the unknown gas

The following data were obtained from the question:

• Rate of unknown gas (R₁) = R
• Rate of CH₄ (R₂) = 3.4R
• Molar mass of CH₄ (M₂) = 16 g/mol
• Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

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