Question

What is the distance, in meters, between adjacent fringes produced by a diffraction grating having 125 lines per centimeter

Answer 1

Answer:

The correct answer will be "9×10⁻³ m".

Explanation:

The given values are:

Number of lines

N = 125

As we know

The distance between the adjacent fringes is:

⇒ $\frac{\lambda x}{d}$

Where, λx = Screen distance

              d = slit width

and,

⇒ $dSin \theta=m \lambda$

Where, $d = \frac{1}{N}$

Hence,

⇒ $\Delta\gamma=\frac{\lambda x}{d}$

          $=\lambda x\times N$

On substituting the values, we get

⇒ $\Delta\gamma=575\times 10^{-9}\times 1.25\times \frac{125}{10^{-2}}$

⇒ $\Delta\gamma=9\times 10^{-3} \ m$