How much energy is required to take 500g of ice at -40 degrees to water at room temperature (22 degrees Celsius)? Show work pls
1 answer:
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Answer:
0.25 N
Explanation:
The density of the ball () = 0.0839 g/cm³ = 83.9 kg/m³
The density of water () = 1000 kg/m³
diameter = 3.77 cm = 0.0377 m
radius of ball = 0.0377/2 = 0.01885 m
The volume (V) =
Let us assume the acceleration due to gravity (g) = 9.8 m/s²
Hence:
The force is required to hold it completely submerged under water (F) is:
F = 0.25 N
Answer:
capacitance of the capacitor = 0.18 μ F
Explanation:
Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²
distance between the plate d = 3.5 × 10–5 m
dielectric value for Teflon K = 2.1
capacitance of capacitor = ?
Formula for capacitance of parallel plate is as follows ,
(Where
)
putting the values in the equation,
C =
=0.18 μ F