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DIA [1.3K]
2 years ago
10

ara h 6 complements ara h 2 as an important marker for ige reactivity to peanut audrey e. koid,† martin d. chapman,†

Chemistry
1 answer:
frez [133]2 years ago
7 0

Purified Ara h 6 will be helpful for research into the immunological mechanisms underlying peanut allergy, including molecular and cellular studies, diagnostic IgE antibody testing, and clinical trials.

1.4% of children and 0.6% of adults in the United States suffer from the food allergy peanut. Approximately 1.8% of youngsters in the UK are allergic to peanuts. Food allergies to milk, eggs, and wheat are often outgrown by children, while allergies to peanuts are more persistent and frequently last into adulthood. As little as 0.4 g of peanut is required to cause milder allergic reactions like rashes, angioedema, and gastrointestinal problems. However, peanut is also one of the leading causes of severe, sometimes fatal anaphylactic reactions.

Learn more about immunological here-

brainly.com/question/14928087

#SPJ4

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Americans spend up to $100 billion annually for bottled water (41 billion gallons). The only beverages with higher sales are car
grigory [225]

<u>Answer:</u> C) be hypertonic to Tank B.

<u>Explanation: </u>

<u> The ability of an extracellular solution to move water in or out of a cell by osmosis</u> is known as its tonicity. Additionally, the tonicity of a solution is related to its osmolarity, which is the <u>total concentration of all the solutes in the solution. </u>

Three terms (hypothonic, isotonic and hypertonic) are used <u>to compare the osmolarity of a solution with respect to the osmolarity of the liquid that is found after the membrane</u>.  When we use these terms, we only take into account solutes that can not cross the membrane, which in this case are minerals.

  1. If the liquid in tank A has a lower osmolarity (<u>lower concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypotonic with respect to the latter.
  2. If the liquid in tank A has a greater osmolarity (<u>higher concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypertonic with respect to the latter.
  3. If the liquid in tank A has the same osmolarity (<u>equal concentration of solute</u>) as the liquid in tank B, the liquid in tank A would be isotonic with respect to the latter.

In the case of the problem, option A is impossible because the minerals can not cross the membrane, since it is permeable to water only. There is no way that the concentration of minerals decreases in tank A, so <u>the solution in this tank can not be hypotonic with respect to the one in Tank B. </u>

Equally, both solutions can not be isotonic and neither we can say that the solution in tank A has more minerals that the one in tank B because the liquid present in tank B is purified water that should not have minerals. Therefore, <u>options B and D are also not correct.</u>

Finally, the correct option is C, since in the purification procedure the water is extracted from the solution in tank A to obtain a greater quantity of purified water in tank B. In this way, the solution in Tank A would be hypertonic to Tank B.

5 0
3 years ago
What would the empirical formula be for the molecular compound CoH904?
Mashutka [201]
It would be the same thing if the Co does not have a number with it because it can’t reduce
5 0
2 years ago
In the titration of HCl with NaOH, the equivalence point is determined
kondaur [170]

Answer:

In the titration of HCl with NaOH, the equivalence point is determined from the point where the phenolphthalein turns pink and then remains pink on swirling.

Explanation:

The equivalence point is the point at which exactly enough titrant (NaOH) has been added to react with all of the analyte (HCl). Up to the equivalence point, the solution will be acidic because excess HCl remains in the flask.

Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10. Phenolphthalein is naturally colorless but turns pink in alkaline solutions. It remains colorless throughout the range of acidic pH levels, but it begins to turn pink at a pH level of 8.3 and continues to a bright purple in stronger alkalines.

It will appear pink in basic solutions and clear in acidic solutions.

The more NaOH added, the more pink it will be. (Until pH≈ 10)

In strongly basic solutions, phenolphthalein is converted to its In(OH)3− form, and its pink color undergoes a rather slow fading reaction and becomes completely colorless above 13.0 pH

a. from the point where the pink phenolphthalein turns colorless and then remains colorless on swirling.

⇒ the more colorless it turns, the more acid the solution. (More HCl than NaOH)

b. from the point where the phenolphthalein turns pink and then remains pink on swirling.

The equivalence point is the point where phenolphtalein turns pink and remains pink ( Between ph 8.3 and 10). (

Although, when there is hydrogen ions are in excess, the solution remains colorless. This begins slowely after ph= 10 and can be noticed around ph = 12-13

c. from the point where the pink phenolphthalein first turns colorless and then the pink reappears on swirling.

Phenolphthalein is colorless in acid solutions (HCl), and will only turn pink when adding a base like NaOH

d. from the point where the colorless phenolphthalein first turns pink and then disappears on swirling

Phenolphthalein is colorless in acid or neutral solutions. Once adding NaOH, the solution will turn pink. The point where the solution turns pink, and stays pink after swirling is called the equivalence point. When the pink color disappears on swirling, it means it's close to the equivalence point but not yet.

3 0
3 years ago
Consider the aldol condensation between dibenzyl ketone and benzil in strong base. Calculate the molar masses of the reactants a
Sati [7]

Answer:

a) 210.3 g/mol

b) 210.2 g/mol

c) 384.5 g/mol

Explanation:

First step we will calculate the molar masses of ; carbon atom, hydrogen atom and  oxygen atom in each .

<u> Molar mass of dibenzyl ketone</u>

Molar mass of dibenzyl ketone = ∑ molar masses of atoms in dibenzyl ketone

= carbon( 15 ) = 15 ( 12.0107 ) + oxygen ( 14 ) = 1 ( 15.999 ) + hydrogen(14) =14(1.00784)

= 210.26926 ≈ 210.3 g/mol

<u>  Molar mass of benzil</u>

Molar mass of Benzil =  ∑ molar masses of atoms in  Benzil

= carbon( 14) = 14(12.0107) + oxygen(2) = 2 ( 15.999) +  hydrogen(10) =10(1.00784)

= 210.2262 ≈ 210.2 g/mol

<u>Molar mass of 2,3,4,5-tetraphenylcyclopentadienone</u>

Molar mass  = ∑ molar masses of atoms

= carbon ( 29) = 29(12.0107) + oxygen (1) = 1( 15.999 ) + hydrogen(20) = 20(1.00784 )

≈ 384.5 g/mol

6 0
3 years ago
Worth 20 points will mark you brainliest!
alexgriva [62]
The one u clicked is the the right one
5 0
3 years ago
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