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Otrada [13]
3 years ago
8

How many hydrogen atoms in 5 H2O?

Chemistry
2 answers:
romanna [79]3 years ago
8 0

Answer:

D

B

B not sure sorry

C

Compound

mamaluj [8]3 years ago
3 0
1: B
2: D
3: C
4: D
5: B
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Can someone answer this please?
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What is the question?? 
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3 years ago
Whats the Number of molecules in 1.500 mole of H2O
deff fn [24]

Answer:

6.02 × 10 23

Explanation:

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2 years ago
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If heat is supplied to the stillpot too rapidly, the ability to separate two liquids by fractional distillation may be drastical
hram777 [196]

Answer: The boiling points of the two liquids are quickly exceeded

Explanation:

Fractional distillation is a method of separating a mixture of liquids where each has different boiling points.

To therefore obtain individual fractions, temperature rise of the mixture must be gradual, otherwise the boiling points of the two liquids will be quickly exceeded making collection of each fraction impossible.

4 0
3 years ago
In the reaction of aluminum metal and oxygen to make aluminum oxide, how many grams of oxygen gas will react with 2.2 moles alum
sweet-ann [11.9K]

Answer:

52.8 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4Al + 3O2 —> 2Al2O3

From the balanced equation above,

4 moles of Al reacted with 3 moles of O2 to produce 2 moles of Al2O3

Next, we shall determine the number of mole of O2 needed to react with 2.2 moles of Al. This can be obtained as follow:

From the balanced equation above,

4 moles of Al reacted with 3 moles of O2.

Therefore, 2.2 moles of Al will react with = (2.2 × 3)/4 = 1.65 moles of O2.

Thus, 1.65 moles of O2 is needed for the reaction.

Finally, we shall determine the mass of O2 needed as shown below:

Mole of O2 = 1.65 moles

Molar mass of O2 = 2 × 16= 32 g/mol

Mass of O2 =?

Mole = mass/Molar mass

1.65 = mass of O2 /32

Cross multiply

Mass of O2 = 1.65 × 32

Mass of O2 = 52.8 g

Therefore, 52.8 g of O2 is needed for the reaction.

4 0
2 years ago
Using the periodic table, answer the following question..How many atoms of neon are in 0.378g of neon (a) 6.02 x 10²³ atoms (b)
zmey [24]

Answer:

B 1.87×10^-²

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20.1797 g Neon = 1 mol

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20.1797y= 0.378 x 1

(Make y the subject of the formula)

y = 0.878/ 20.1787

y = 0.0187317

y = 0.0187 approx

y = 1.87 x 10^-²

7 0
3 years ago
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