Question

Q|C Classical general relativity views the structure of space-time as deterministic and well defined down to arbitrarily small distances. On the other hand, quantum general relativity forbids distances smaller than the Planck length given by L= (hG/c³)¹/².(b) Calculate this time interval, known as the Planck time T , and state how it compares with the ultrahot epoch mentioned in the text.

Answer 1

(b) The Planck time is given as

      T=$\frac{L}{C} =\frac{1.62*10^{-35}m }{2.998*10^{8}m/s }$

        =5.39×$10^{-44}s$

of the same order of magnitude as the ultra hot epoch

What exactly is Planck Time?

• The Planck time is the fundamental unit of time in the Planck Unit system. It has the following worth:

• $t_{p}$=5.39×$10^{-44}s$

• Measurements of time in SI units are made in seconds (usually given the symbol s). Although measuring the time it takes an athlete to sprint 100 meters or the length of a phone call in seconds is convenient in everyday life, it becomes less practical when discussing the sequence of events that occurred in the very early Universe (such as the onset of inflation that occurred 10-35s after the Big Bang).

• The entire geometry of spacetime predicted by general relativity breaks down at this scale. As a result, to describe the laws of physics on such scales, an as-yet undiscovered theory combining general relativity and quantum mechanics is required. As a result, our current descriptions of the Universe's early evolution begin at  $t_{p}$=5.39×$10^{-44}s$  seconds after the Big Bang.

To learn more about Planck Time refer to

brainly.com/question/26117248

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