Answer: The head temperature rises as the vapors of lower-boiling compound fill the distillation head. The temperature drops because the lower-boiling compound finishes distilling before vapors of the higher-boiling compound can fill the distillation head, which then cause the head temperature to rise.
What's going on is that the water in the straw is pushed into the straw by the air pressure outside of the straw. As long as the pressure outside is able to overcome the force of gravity, the liquid will stay in the straw.
Answer:
image is 14.47 cm behind the lens
height is 2.11 mm
Explanation:
Given data
h = 2.03 cm
p = 1.39 m = 139 cm
focal-length f = 131 mm = 13.1 cm
to find out
Where is the image and How high is it
solution
we know focal length formula that is
1/f = 1/p + 1/q
put here value to find q
1/ 13.1 = 1/ 139 + 1 solbe/ q
q = 14.463066 cm
so image is 14.47 cm behind the lens
and
height is calculate
height / h = - q / p
put here all value
height = -14.47 / 139 × 2.03
height = −0.211324 cm
here -ve sign show image is inverted
so height is 2.11 mm
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by
<span>C = 2L = 2*pi*R ---> R = L/pi </span>
<span>Now define the center of the semi-circle as the origin of coordinates and define a as the angle between R and the x-axis. </span>
<span>we can define a small charge dq as </span>
<span>dq = l*ds = l*R*da </span>
<span>So the electric field can be written as: </span>
<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>
<span>E = pi*k*Q/L(sin(a)/L I_hat - cos(a)/L j_hat)</span>
